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4 years ago

Which change represents an increase in the entropy system

1 answer:

3 0

Answer: Entropy increases when a substance is broken up into multiple parts. The process of dissolving increases entropy because the solute particles become separated from one another when a solution is formed.

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A student makes observations when water is added to a blue solution of copper sulfate. The student makes only 1 observation: the

horrorfan [7]

No, I believe this is not an example of a chemical reaction. What we actually see here is a physical change of the solution. Since we are adding more water to an aqueous solution which is also made up mostly of water, what we are simply basically doing is dilution. Since the solution is being diluted, so definitely the color turned lighter.

6 0

3 years ago

A 10 M concentrated stock solution of NaCl was used to prepare 5 liters of diluted 1 M solution. Which of the following statemen

vfiekz [6]

Answer:

D. The volume of the solvent used was less than 5 liters.

Explanation:

We have the rule: the no. of moles before dilution equal the no. of moles after dilution.

(MV) before dilution = (MV) after dilution.

M before dilution = 10.0 M, V before dilution = V of stock = ??? L.

M after dilution = 1.0 M, V after dilution = 5.0 L.

V before dilution = V of stock = (MV) after dilution/M before dilution = (1.0 M)(5.0 L)/(10.0 M) = 0.5 L.

∴ The volume of the stock used is 0.5 L.

The volume of the solvent used is 4.5 L.

So, the right choice is:

D. The volume of the solvent used was less than 5 liters.

7 0

3 years ago

Read 2 more answers

You are given three cubes, A, B, and C; one is magnesium, one is aluminum, and the third is silver. All three cubes have the sam

katovenus [111]

Answer:

The cube A is magnesium, the cube B is aluminum and the cube C is silver.

Explanation:

Density is defined by the expression $d=\frac{m}{V}$ where m is the mass and V is the volume, therefore:

- Density of the cube A:

$d_{A}=\frac{m_{A}}{V_{A}}$

- Density of the cube B:

$d_{B}=\frac{m_{B}}{V_{B}}$

- Density of the cube C:

$d_{C}=\frac{m_{C}}{V_{C}}$

Solving for mass:

$m_{A}=d_{A}*V_{A}$

$m_{B}=d_{B}*V_{B}$

$m_{C}=d_{C}*V_{C}$

And all the three cubes have the same mass, so:

$m_{A}=m_{B}=m_{C}$

Therefore:

$d_{A}*V_{A}=d_{B}*V_{B}$ (Eq.1)

$d_{A}*V_{A}=d_{C}*V_{C}$ (Eq.2)

Solving for $d_{1}$ in Eq.1:

$d_{A}=d_{B}\frac{V_{B}}{V_{A}}$

Replacing values for the volume:

$d_{A}=d_{B}\frac{16.7mL}{25.9mL}$

$d_{A}=d_{B}*0.64$

As we know the density of the aluminum is $2.7\frac{g}{cm^{3}}$ , so replacing this value for $d_{B}$ :

$d_{A}=2.7\frac{g}{mL}*0.64$

$d_{A}=1.728\frac{g}{mL}$

that is the density of the magnesium.

Solving for $d_{C}$ in Eq.2:

$d_{C}=d_{A}\frac{V_{A}}{V_{C}}$

$d_{C}=d_{A}\frac{25.9mL}{4.29mL}$

$d_{C}=d_{A}*6.04$

$d_{C}=1.728\frac{g}{mL}*6.04$

$d_{C}=10.4\frac{g}{mL}$

That is the density of the silver.

Therefore the cube A is magnesium, the cube B is aluminum and the cube C is silver.

8 0

4 years ago

A change in which property of light will have no effect on whether or not the photoelectric effect occurs??? Frequently energy i

slavikrds [6]

Intensity has no affect on whether or not the photoelectric effect occurs. The determining property is frequency and since frequency and wavelength are inversely proportional, wavelength matters as well. If a frequency of light can't cause the photoelectric effect to happen, no matter what the intensity is, the light can't make it happen.

I hope this helps. Let me know in the comments if anything is unclear.

5 0

3 years ago

Read 2 more answers

Alcano con 1 carbono?

never [62]

creo esto te va a ayudar

5 0

3 years ago