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EastWind [94]
3 years ago
8

What is the element for Trifluoroborane

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
7 0

<span>Ethoxyethane; trifluoroborane; BF3.Et2O; Boron trifluoride ethyl ether; Boron trifluoride diethyl ether; Boron trifluoride-diethyl ether; Boron 

</span>
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100 POINTS+BRAINLIEST: How do you balance a chemical equation step by step? Please explain in simple language, give definitions
bogdanovich [222]

Answer:

list all the elements.

you need to find a number to multiply both sides to get the same result.

example: I said on the left side: 5×O2 which is 10. on the right side I do the same to get 10.

In order to do this I said: 4×H2O which is 8 H2,and 4 O.

I then said 3×CO2 which gives 3 C and 6 O2. 6+4=10.

Now Oxygen(O) is balanced. Do the same for the rest of the elements.

Explanation:

pls mark as brainliest thanks!

7 0
2 years ago
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How is condensation explained by the Kinetic Molecular Theory? Cooling reduces particle motion, resulting in coalescence by attr
lara31 [8.8K]

Temperature means, in this context, movement.

Condensation can be explained by the reduction of temperature of the system. This effect make possible the cohesion forces increases. In other words, the result is coalescence by attractive forces.

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3 years ago
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Is the process by which certain waste materials, such as plastic, glass, aluminum, and paper, are prepared for reuse.
andriy [413]
the process is called recycling.
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4 years ago
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You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye
dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

V = 10 mL solution

V_{added} = 12.20 mL

V_{total} = 22.20 mL

then,

M 0.103 M of NaOH,

V_{rinsed} = experiment  will not be affected

V_{total \ base} = 10.38 mL

Now,

⇒  mol of NAOH = MV

                            = 0.103\times 10.38

                            =  1.06914  \ m

Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

⇒  mol \ of \ acid =\frac{1}{2}\times \ mol \   of  \ base

⇒  1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid

Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

                 =\frac{ 0.53457 }{10}

                 =0.053457 \ M (Sulfuric acid)

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3 years ago
QUESTION ABOUT IONIC COMPUND DUE IN 7 MINUTES URGENT!!!!!!!!!!!!!
nekit [7.7K]

Answer:

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