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3 years ago

A classroom has students sitting in 5 columns of 5,6,7,5 and 2. What are the mean, median, mode, and range of class columns.

2 answers:

7 0

To find the mean= add all numbers then divide by the amount of numbers there are

25/5=5

So, mean=5

To find the median- order the numbers from least to greatest, then look for the middle number.

2, 5, 5, 6, 7

The middle number is 5, so the median is 5.

To find the mode, look for the most commonly used number. 5 is used twice, which is the most, so 5 is the mode.

To find the range, subtract the smallest number from the largest number.

7-2=5

So, the range is 5.

In summary:

Mean: 5
Median: 5
Mode: 5
Range: 5

Hope this helps! Comment if you have any questions or concerns!

maria [59]3 years ago

5 0

Mean: 5
Median: 5
Mode: 5
Range: 5

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2 years ago

Read 2 more answers

A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.

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in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}$

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}$

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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

larisa86 [58]

Answer: (C) divide by 1

Step-by-step explanation:

when dividing by x - 1, set the expression equal to zero to find the zero. That is actually what you are dividing by:

x - 1 = 0 ⇒ x = 1

so the number outside of the synthetic division symbol is 1.

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