All categories

2 years ago

What is the y-intercept of a line perpendicular to y = x + 6 that passes through the point (4 ,-3)?

Mathematics

1 answer:

Reika [66]2 years ago

3 0

Answer:

I believe it to be C

Step-by-step explanation:

You might be interested in

The minimum score on the SAT test is 600 and the maximum score is 2400. Write an absolute value equation that represents the min

Inessa [10]

X greater than/equal to 600 and X less than/equal to 2400

6 0

3 years ago

Read 2 more answers

4 times a number less than 7 times the same number is 24. Find the number.

Afina-wow [57]

Answer:

the number is 1

Step-by-step explanation:

4(7n-n)=24

28n-4n=24

24n=24

n=1

7 0

2 years ago

Read 2 more answers

Find the mean median mode<br> 12,9,12,11,10,18,7,19,13,19

Nady [450]

Mean : The average of all the data in a set.

Median : The value in a set which is most close to the middle of a range.

Mode : The value which occures most frequently in a data set.

12,9,12,11,10,18,7,19,13,19

Mean = 13 (Average)

Median = 12 (Middle)

Mode = 12, 19 (most common)

8 0

3 years ago

Use the box method to distribute and simplify (-5x-2)(-2x^2+6x).

Mkey [24]

Answer:

$10x^{3} - 26x^{2} - 12x$

Step-by-step explanation:

1) Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

$10x^{3} - 30x^{2} + 4x^{2} -12x$

2) Collect like terms.

$10x^{3} + (-30x^{2} +4x^{2} )-12x$

3) Simplify.

$10x^{3} - 26x^{2} -12x$

Therefor, the answer is, 10x^3 - 26x^2 - 12x.

3 0

2 years ago

Cual es la derivada de ()=√x sin

fgiga [73]

Answer:

$f(x) =\sqrt{x} sin (x)$

And on this case we can use the product rule for a derivate given by:

$\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)$

Where $f(x) =\sqrt{x}$ and $g(x) =sin (x)$

And replacing we have this:

$f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)$

Step-by-step explanation:

We assume that the function of interest is:

$f(x) =\sqrt{x} sin (x)$

And on this case we can use the product rule for a derivate given by:

$\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)$

Where $f(x) =\sqrt{x}$ and $g(x) =sin (x)$

And replacing we have this:

$f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)$

3 0

2 years ago