Multiply everything in the second parenthesis by x.
-3x^3 + 3x^2 + x
Multiply everything in the second parenthesis by 2.
-6x^2 + 6x + 2
Combine these two equations together.
-3x^3 + 3x^2 + x - 6x^2 + 6x + 2
Combine like terms.
-3x^3 - 3x^2 + 7x + 2
Hope this helps!
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Answer: B&E
The answer is b and c I hope dat help
Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
I think the. answer is 511.2
