Hi Braniac
S = his speed for the 1st 20 mi
(s-2) = His speed for the last 16 mi
We know that :
time= distance/ speed
initial time = cool down time
20/s = 16/(s-2)
Now cross multiply
20(s-2) =16s
20s-40=16s
20s-16s=40
4s = 40
Now we need to divide both sides by 4 so we can find the speed
4s/4 = 40/4
s= 10 mph
His initial speed is 10mph
Now let's find his cool down speed
10-2 = 8mph
His cool down speed is 8mph
I hope that's help :)
If you have any questions please let me know :)
Answer:
5-x=9x^2
y=5-x
Step-by-step explanation:
It’s d the minimum value is 1 of the graph
Using the order of operations (PEMDAS)...
23 · 1 - 1 = ?
23 - 1 = ?
22
The answer is 22
Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
Question :
5m^2 - 29m + 20
Steps:
What can u factor to get 20?
you can make 5 and 4 to make 20 so,..
1. Break it into groups
(5m^2 - 4m) + (-25m + 20)
*Factor out m from (5m^2 - 4m) : m(5m - 4)
*Factor out -5 from (-25m + 20) : -5(5m - 4)
2. Then, you can factor out the common term : (5m - 4) because they both have it. And then u would move the m by the -5 so,...
= (5m - 4)(m - 5) <======= <em>Answer</em>
Hope this helped!!!
~Shane