The set of points (–4, 2), (–2, 4), (2, 4), and (4, 2) identifies the vertices of a quadrilateral. Which is the most specific de
scription to tell which figure the points form?
1 answer:
Answer:
Isosceles trapezoid
Step-by-step explanation:
Plotting the points show us that this shape is at least a trapezoid, by the fact that only one pair of parallel sides.
To show that it is isosceles is done by finding the lengths of the diagonals, which takes quite long, but here, it is very clear that the two non-parallel sides are congruent, and the parallelogram is perfectly symmetrical.
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Answer:
The answer is .
Step-by-step explanation:
First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element there exist another element, denoted by
such that
, where
stands for the identity element of G.
So, given the equality we make a left multiplication by
and we obtain:
But, . Hence,
.
Now, in the equality we make a right multiplication by
, and we obtain
.
Recall that and
. Therefore,
.