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GaryK [48]
2 years ago
8

How far will a car travel if its velocity is 15 m/s in 3 seconds? Follow example below.

Physics
1 answer:
svet-max [94.6K]2 years ago
4 0
<h3><u>Solution</u><u>:</u></h3>
  • Distance (d) = 112 m
  • Time (t) = 4 seconds
  • Let the speed be v.
  • We know, speed = Distance / Time
  • Therefore, v = d/t

or, v = 112 m ÷ 4 s = 28 m/s

<h3><u>Answer</u><u>:</u></h3>

<u>The </u><u>speed </u><u>of </u><u>the</u><u> </u><u>cheetah</u><u> </u><u>is </u><u>2</u><u>8</u><u> </u><u>m/</u><u>s.</u>

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Answer:

Whether the force exerted by the locomotive on the wall was larger

Than the force the locomotive could exert on the wall.

Explanation:

The Newton's third law of motion States that every force have it's equal and opposite reaction force, whose magnitude is the same as the applied force. Therefore the magnitude of these opposite forces will be equal.

So we have;

F12=-F21

F12 is the force in a direction

-F21 is the force in the opposite direction.

Therefore we see that the magnitude of the force the locomotive exerts on the wall is equal to the one the wall exerts on the locomotive. Both magnitudes are equal but in opposite directions.

6 0
3 years ago
Starting at point 0, you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees. What is your heigh
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Answer:

43.58 m

Explanation:

If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees

Using trigonometry ratio

Sin 5 = opposite/hypothenus

Where the hypothenus = 500m

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Sin 5 = h/500

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500 × sin 5 = h

h = 500 × 0.08715

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Therefore, the height above the starting point is equal to 43.58m

5 0
3 years ago
I dont know how to do question 3,4
dlinn [17]

<span>Prior to the Cambrian, organisms with hard parts (eg. shells and bones) weren't present for most the time, and it's generally such hard parts that get to fossilize. There's also been more time for Precambrian deposits to get destroyed by natural processes, </span>

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3 years ago
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soldi70 [24.7K]
Limestone, Sandstone, and Shale would be the answer.

4 0
3 years ago
A spotlight on the ground shines on a wall 15 meters away. A man 1.8 meters tall walks away from the spotlight toward the buildi
Alex17521 [72]

Answer:

s=(15-x)m

Explanation:

Let the distance from spotlight to wall be 15m, and distance from the man to the building be x.

#Therefore the height of the shadow as a function of the above is s=(15-x )m

Hence, height of the shadow is expressed as s=(15-x)m

#See attached photo for illustration

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3 years ago
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