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Svetradugi [14.3K]
3 years ago
12

An empty truck traveling at 10 km/h has kinetic energy. How much kinetic energy does it have when loaded so that its mass and it

s speed are both doubled?
Physics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

8 time increase in K.E.

Explanation:

Consider Mass of truck = m kg and speed = v m/s then

K.E. = 1/2 ×mv²

If mass and speed both are doubled i.e let m₀ = 2m and v₀ = 2v then

(K.E.)₀ =  1/2 ×2m(2v)²

(K.E.)₀ = 8 (1/2 × mv²) = 8 × K.E.

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True or False- For resistors in series, the larger the resistance is, the larger the voltage drop that is required.​
WINSTONCH [101]

Answer:

I think its true

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3 years ago
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How does the temperature affect the phase of water
Sever21 [200]

Answer:

Temperature affects phase change by slowing down the movement in between the atoms, thus causing a change in kinetic energy, which in turn causes the atoms to undergo forms of combining or a type of disepersion.

Explanation:

Kinetic energy while being the reason phase changes are constant, Kinetic Energy can be caused by other means. Pressure and temperature can affect many other states kinetic energy, which in turn can affect each state of matter. Making a group of atoms or compounds compacts will force the atoms to move closer together thus with a lower net kinetic energy energy. Reducing temperature also works along the same lines. Colder temperatures can slow down atomic movements which in turn will naturally make each atom move close to each other.

With all of the information provided, it is only feasible that pressure and temperature are directly corresponding with the matter and atomic phase change

8 0
2 years ago
If the average gauge pressure in the vein is 12200 Pa, what must be the minimum height of the bag in order to infuse glucose int
Amanda [17]

Answer:

h = 1.22 m

Explanation:

Given:

Pressure in the vein = 12200 Pa

Specific gravity of the liquid  = 1.02

now,

the pressure due to a fluid is given as:

P = pgh

where,

P is the pressure,

ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³

ρ = 1020 kg/m³

g is the acceleration due to the gravity = 9.81m/s²

h is the height

thus,

h = P/pg =\frac{12200}{1020\times 9.8}=1.22 m

6 0
3 years ago
A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov
Rina8888 [55]

Answer:

20.96 m/s

Explanation:

Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

t = time of flight of the puck = ?

2 = (0)(t) + 9.8 t²/2

4.9t² = 2

t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

uₓ = horizontal component of the initial velocity = 20 m/s

g = 0 m/s² as there's no acceleration component in the x-direction

t = 0.639 s

x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m

For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

vᵧ² = uᵧ² + 2gy

vᵧ² = 0 + 2×9.8×2

vᵧ = 6.26 m/s

vₓ = 20 m/s, vᵧ = 6.26 m/s

Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s

4 0
3 years ago
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The voltage across a 5-uF capacitor is: v (t )equals 10 cos open parentheses 6000 t close parentheses space straight V. What is
mamaluj [8]

Answer:

- 0.3sin6000t A

Explanation:

Voltage, v = 10 cos 6000t V

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Current flowing through, i(t)

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c = 5-uF = 5 * 10^-6 F

i(t) = (5 * 10^-6) * d/dt(10 cos 6000t)

d/dt(10 cos 6000t) = (10 * 6000) * (-sin 6000t)

Hence,

i(t) = (5*10^-6) * (10*6000) * (-sin 6000t)

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i(t) = 30 * 10^-2 * - sin6000t

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4 0
3 years ago
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