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Svetradugi [14.3K]
3 years ago
12

An empty truck traveling at 10 km/h has kinetic energy. How much kinetic energy does it have when loaded so that its mass and it

s speed are both doubled?
Physics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

8 time increase in K.E.

Explanation:

Consider Mass of truck = m kg and speed = v m/s then

K.E. = 1/2 ×mv²

If mass and speed both are doubled i.e let m₀ = 2m and v₀ = 2v then

(K.E.)₀ =  1/2 ×2m(2v)²

(K.E.)₀ = 8 (1/2 × mv²) = 8 × K.E.

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Answer:

V=W/Q

107V= W/17C

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= 1819 J

Explanation:

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3 years ago
What happens when a force is applied to an object in stable equilibrium
Katarina [22]

Answer:

the object is no longer in equilibrium .

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When calculating global population growth, the death rate is subtracted from the birth rate
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Read 2 more answers
3. What average net force is required to stop a 7 kg shopping cart in 2 s if it's initially
stiv31 [10]

-12.25N

Explanation:

Given parameters:

Mass of shopping cart = 7kg

Time = 2s

initial velocity = 3.5m/s

Unknown:

Average net force required to stop the cart = ?

Solution;

According to newton's second law"acceleration of body results when a net force acts on a body".

    F = ma

where F is the force

           m is the mass

            a is the acceleration

Acceleration is the change in velocity with time

     a = \frac{v - u}{t}

Therefore;

     F = m x  \frac{v - u}{t}

v is the final velocity, in this case it is zero, 0

u is the initial velocity

t is the time taken

    Putting in the parameters:

      F =  7 x  \frac{0- 3.5}{2} = -12.25N

This force that will stop the cart will be directed in the opposite direction with a magnitude of 12.25N

Learn more:

Newton's law brainly.com/question/11411375

#learnwithBrainly

8 0
3 years ago
Two objects, with masses m1 and m2, are originally a distance r apart, and the magnitude of the gravitational force on each one
Alex787 [66]

Explanation:

It is given that, two objects, with masses m₁ and m₂, are originally a distance r apart, and the magnitude of the gravitational force on each one is F. If the objects are moved a distance 2 r apart, we need to find the new gravitational force.

The gravitational force is given by :

F=G\dfrac{m_1m_2}{r^2}...........(1)

Let the force is F' when the objects are moved a distance 2 r apart. So,

F=G\dfrac{m_1m_2}{(2r)^2}

F'=\dfrac{1}{4}G\dfrac{m_1m_2}{r^2}

F'=\dfrac{1}{4}F            (from equation (1))

So, it is clear that the magnitude of new force is F/4 i.e. decreases by a factor is 1/4. Hence, this is the required solution.

8 0
3 years ago
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