Answer:
(B) 1.17 m.
Explanation:
At the highest point, the conservation of energy equation would becomes;
K.E (initial ) = K.E + P.E;
½ m(V)^2 = ½ m(V)^2 + mgh
(m*6^2)/2 = (m * 9.81 * 1.1) + (m*V^2)/2
36/2 = (9.81 * 1.1) + v^2/2
Solving the equation;
v=√14.44 m/s
= 3.8 m/s
a = −0.6g
= -0.6*9.81
= −5.88 m/s^2
Using equation of motion,
V^2 = U^2 + 2aS
S = V^2/2a
= 14.44/12
= 1.19 m.
E force needed to accelerate a 68 kilogram-skier at a rate of
1.2
m
s
2
is 81.6 Net forces.
Explanation:
Take the mass(68kg) and the acceleration of the skier(
1.2
m
s
2
) and multiply them together
<span>The primary service used by stations to exchange mac frames when the frame must traverse the ds to get from a station in one bss to a station in another bss is Distribution
In this type of service, the bss is required in order to build the basic building block for the wireless LAN</span>
its because it allows modern astronomers the ability to see farther out and more accuratly