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adell [148]
4 years ago
6

4. The time it takes an object to rotate once is ​

Physics
1 answer:
pshichka [43]4 years ago
3 0

Answer:

Explanation:

23.9344696 hours

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How much kinetic energy does a 55 kg object have that is traveling 20m/s?
shutvik [7]

Answer:

11000 J

Explanation:

Apply the formula: K = 1/2.m.v²

K = 1/2.55.20²

K = 1/2.55.400

K = 55.200

K = 11000 Joules

4 0
3 years ago
Read 2 more answers
A tennis player practices against a wall, hitting a 0.1 kg ball towards the
pantera1 [17]

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

3 0
3 years ago
Which phrase is the best definition of matter?
Alexxandr [17]

Answer:

C is the correct answer

please keeps as Brainly list

3 0
3 years ago
A bob of mass m = 0.250 kg is suspended from a fixed point with a massless string of length L = 22.0 cm. You will investigate th
katen-ka-za [31]

To solve the problem, it is necessary to use the concepts of gravitational force, centripetal force and trigonometric components that can be extrapolated from the statement.

By definition we know that the Force of Gravity is given by

F_g=mg

Where,

m= Mass

g = Gravitational Acceleration

The centripetal force is given by,

F_c = \frac{mv^2}{R}

Where,

m = Mass

v = Velocity

R = Radius

For the case described in the problem, the Force of gravity the net component would be given by sin?, While for the centripetal force the net component is in the horizontal direction, therefore it corresponds to the cos\theta

Then,

F_g = mg sin\theta

F_c = \frac{mv^2}{r}cos\theta

From the radius we have its length but not the net height, which would be given by

r = L sin\theta

So equating the equations we have to

F_g = F_c

mg sin\theta=\frac{mv^2}{r}cos\theta

mg sin\theta=\frac{mv^2}{Lsin\theta}cos\theta

Re-arrange to find v,

v = \sqrt{\frac{gLsin^2\theta}{cos\theta}}

Replacing with our values

v = \sqrt{\frac{(9.8)(22*10^{-2})(sin^2 24)}{cos24}}

v = 0.624

Therefore the tangential velocity of the mass is 0.624m/s

5 0
4 years ago
I NEED THIS QUICKLY
Zina [86]

Answer:

A

Explanation:

SInce It is peaking at the top that's where energy is stored

8 0
3 years ago
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