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Molodets [167]
3 years ago
6

Initially, 0.05kg of air is contained in a piston cylinder device at 200 oc and 1.6 mpa. the air then expands at constant temper

ature to a pressure of 0.4 mpa. assume the process occurs slowly enough that the acceleration of the piston can be neglected. the ambient pressure is 101.35kpa. (i) determine the work (kj) performed bt the air in the cylinder on the piston. (ii) determine the work (kj) performed by the piston on the ambient environment. neglect the cross-sectional area of the connecting rod. (iii) determine the work transfer (kj) from the piston to the connecting rod. neglect friction between the piston and cylinder. assume that no heat transfer to or from the piston occurs and that the energy of the piston does not change solution
Physics
1 answer:
myrzilka [38]3 years ago
6 0
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
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PLZZZZZ ANSWER Which example describes a nonrenewable resource?
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Answer:

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Explanation:

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7 0
3 years ago
Read 2 more answers
The mass of a hot-air balloon and its cargo (not including the air inside) is 170 kg. The air outside is at 10.0°C and 101 kPa.
scoundrel [369]

Answer:

108.37°C

Explanation:

P₁ = Initial pressure = 101 kPa

V₁ = Initial volume = 530 m³

T₁ = Initial temperature = 10°C = 10+273.15 =283.15 K

P₂ = Final pressure = 101 kPa (because it is open to atmosphere)

V₂ = Final volume = 530 m³

P₁V₁ = n₁RT₁

⇒101×530 = n₁RT₁

⇒53530 J = n₁RT₁

P₂V₂ = n₂RT₂

⇒53530 J = n₂RT₂

\frac{m_1}{m_2}=\frac{\rho V_1}{\rho V_1-170}\\\Rightarrow \frac{m_1}{m_2}=\frac{1.244\times 530}{1.244\times 530-170}=1.347\\\Rightarrow \frac{m_1}{m_2}=1.347\\\Rightarrow \frac{n_1}{n_2}=1.347

Dividing the first two equations we get

1=\frac{n_1}{n_2}\frac{T_1}{T_2}\\\Rightarrow 1=1.347\frac{283.15}{T_2}\\\Rightarrow T_2=1.347\times 283.15= 381.52\ K

∴Temperature must the air in the balloon be warmed before the balloon will lift off is 381.25-273.15 = 108.37°C

8 0
3 years ago
The main energy source during exercise of low to moderate intensity is
zhannawk [14.2K]

Answer:

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Explanation:

6 0
3 years ago
Generally you must stir a can of paint before you use it.. is paint miscible or immiscible? explain
Wewaii [24]

Paint is immiscible because the layer that forms on top of settled paint is a substance which cannot dissolve with the rest of the paint.  Stirring the paint is only temporarily in effort to form an even and thoroughly mixed solution by physically mixing the separate molecules of the solution.  However, for it to be miscible, it the solution has to be evenly distributed (chemically) on a molecular level as to not separate when left for a lengthy period of time.

6 0
3 years ago
A coil of wire consists of 20 turns, each of which has an area of 0.0015 m2. A magnetic field is perpendicular to the surface wi
stepan [7]

Answer:

magnitude of the induced emf in the coil is 0.0153 V

Explanation:

Given data

no of turns = 20

area = 0.0015 m²

magnitude  B1 = 4.91 T/s

magnitude  B2 = 5.42 T/s

to find out

the magnitude of the induced emf in the coil

solution

we know here

emf = -n A d∅ /dt

so here n = 20 and

A = 0.0015

and d∅ = B2 - B1 = 5.42 - 4.91

d∅ = 0.51 T and dt  at 1 sec

so  put all value

emf = -n A d∅ /dt

emf = -20 (0.0015) 0.51 / 1

emf = - 0.0153

so magnitude of the induced emf in the coil is 0.0153 V

7 0
3 years ago
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