Answer: An Incident on Route 12 is presented here in a high quality paperback edition. This popular classic work by James H. Schmitz is in the English language, and may not include graphics or images from the original edition.
Explanation: I HOPE THAT HELPED
Answer:
k1 + k2
Explanation:
Spring 1 has spring constant k1
Spring 2 has spring constant k2
After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.
x1 = x2
Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are
k1 = F1/x -> F1 =k1*x
k2 = F2/x -> F2 =k2*x
While F = F1 + F2
Substitute equation of F1 and F2 into the equation of sum of forces
F = F1 + F2
F = k1*x + k2*x
= x(k1 + k2)
Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)
Considering the general equation of spring forces (Hooke's Law) F = kx,
The effective spring constant for the system is k1 + k2
Explanation:
The moon is the earth satellite and it orbits our blue planet. Earth, moon and mercury are all rock materials in the solar system. They are all made up of dense silicate balls of rocks.
- The Earth and Mercury are made up of silicate minerals and some iron core but the moon is predominant made up of silicate balls.
- The earth has liquid water on it's surface but the moon has no liquid water.
- The earth is an active planet in terms of tectonic activity. The moon is not active tectonically.
Learn more:
moon brainly.com/question/12785992
#learnwithBrainly
Answer:
When the object is placed at the focus the image is formed at infinity.
Explanation:
When a ray passes through focus and incident on a concave mirror then it will travel parallel to principal axis after reflection.Hence the image is formed at infinity.
Answer:
The answer is "Choice C ".
Explanation:
The relationship between the E and V can be defined as follows:
Let,
When E=0
v is a constant value
Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.
