The work done by a constant force in a rectilinear motion is given by:
where F is the magnitude of the force, d is the distance and θ is the angle between the force and the displacement vector.
In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:
Therefore, the total work done is 578.123 J and the answer is option E
Answer: The correct answer is "magnetic field".
Explanation:
A magnetic field is produced around the current carrying wire.
If you bring compass needle around the current carrying wire then it shows the deflection which indicates that there is a magnetic field around the current carrying wire.
Magnetic fields are the area around the surrounding of magnet in which magnetic force can be experienced.
Therefore, a magnetic field is produced around a wire when an electrical current is in the wire.
Answer:
x-component=-9.3 m
Magnitude of A=17.7m
Explanation:
We are given that
We have to find the x-component of A and magnitude of A.
According to question
Substitute the values then we get
m
The value of x-component of A is negative because the vector A lie in second quadrant.
Hence, the x- component of A=-9.3 m
The third one sliding friction
Explanation:
