Which two factors does the power of a machine depend on?

A truck is traveling 20m/s accelerates 3 m/s^2 for 4 seconds how far did it travel while it was accelerating. Using guess method

stellarik [79]

<h3> $\huge\underline\bold\blue{ƛƝƧƜЄƦ}$ </h3><h3>Given</h3>

$\blue\star$ v = 20m\s

$\blue\star$ a = 3m\s^2

$\blue\star$ t = 4sec

Firstly we have to find u

$\star$ a = $\dfrac{v - u}{t}$

$\star$ 3m\s = $\dfrac{20 - u}{4}$

$\star$ 12m\s = 20 - u

$\star$ 20 - u = 12m\s

$\star$ - u = -8

$\star$ u = 8

Now we can easily find distance by using second equation of motion

$\red\star$ s = ut + 1\2 at^2

$\red\star$ s = 8(4) + 1\2(3)(16)

$\red\star$ s = 32 + 24

$\red\star$ s = 56

So distance is 56 m\s hope it helps

5 0

2 years ago

Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.

Cloud [144]

Answer:

The magnitude of the electric field at a point equidistant from the lines is $4.08\times10^{5}\ N/C$

Explanation:

Given that,

Positive charge = 24.00 μC/m

Distance = 4.10 m

We need to calculate the angle

Using formula of angle

$\theta=\sin^{-1}(\dfrac{\dfrac{d}{2}}{2d})$

$\theta=\sin^{-1}(\dfrac{1}{4})$

$\theta=14.47^{\circ}$

We need to calculate the magnitude of the electric field at a point equidistant from the lines

Using formula of electric field

$E=\dfrac{2k\lambda}{r}\times2\cos\theat$

Put the value into the formula

$E=\dfrac{2\times9\times10^{9}\times24.00\times2\times10^{-6}\cos14.47}{2.05}$

$E=408094.00\ N/C$

$E=4.08\times10^{5}\ N/C$

Hence, The magnitude of the electric field at a point equidistant from the lines is $4.08\times10^{5}\ N/C$

6 0

2 years ago

Which of the following is a component of staying positive while competing

Natalija [7]

Answer: B - complimenting others on good plays

Explanation: Reading the first words sort of give it away when staying positive you compliment, not criticize, confront angrily, or refuse.

4 0

2 years ago

Read 2 more answers

Question 9:<br> All parts thank you !

WINSTONCH [101]

Photo Math is the answer

5 0

3 years ago

estion: Why is it important to use vector quantities and not just scalar quantities to describe the motion of an object? Vector

Vera_Pavlovna [14]

Answer:

Vector quantities are important in the study of motion. Some examples of vector quantities include force, velocity, acceleration, displacement, and momentum. The difference between a scalar and vector is that a vector quantity has a direction and a magnitude, while a scalar has only a magnitude. Vector, in physics, a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. A quantity which does not depend on direction is called a scalar quantity. Vector quantities have two characteristics, a magnitude and a direction. The resulting motion of the aircraft in terms of displacement, velocity, and acceleration are also vector quantities. A vector quantity is different to a scalar quantity because a quantity that has magnitude but no particular direction is described as scalar. A quantity that has magnitude and acts in a particular direction is described as vector.

Explanation:

8 0

2 years ago