Which two factors does the power of a machine depend on?

A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in

Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

$d_x = 3.65-1.91=1.74 m$

While the displacement in the y-direction is:

$d_y = -4.79 -(-2.73)=-2.06 m$

The time taken is t = 304 s.

So the components of the average velocity are:

$v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s$

$v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s$

And the magnitude of the average velocity is

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s$

8 0

3 years ago

What is the expected fuel consumption for a 500-nautical mile flight under the following conditions? Pressure altitude 4,000 ft

aleksandr82 [10.1K]

Answer: 36.1 gallons

Explanation:

5 0

2 years ago

What is "lake-effect" and how does it make snow storms worse

son4ous [18]

Is produced during cooler atmospheric conditions when a cold air mass moves across long expanses of warmer lake water. The lower layer of air, heated up by the lake water, picks up water vapor from the lake and rises up through the colder air above; the vapor then freezes and is deposited on the leeward (downwind) shores.[1]

The same effect also occurs over bodies of salt water, when it is termed ocean-effect or bay-effect snow. The effect is enhanced when the moving air mass is uplifted by the orographic influence of higher elevations on the downwind shores. This uplifting can produce narrow but very intense bands of precipitation, which deposit at a rate of many inches of snow each hour, often resulting in a large amount of total snowfall.

The areas affected by lake-effect snow are called snowbelts. These include areas east of the Great Lakes, the west coasts of northern Japan, the Kamchatka Peninsula in Russia, and areas near the Great Salt Lake, Black Sea, Caspian Sea, Baltic Sea, Adriatic Sea, and North Sea.

7 0

3 years ago

A sample of tendon 3.00 cm long and 4.00 mm in diameter is found to break under a minimum force of 128 N. If instead the sample

Degger [83]

It must be the same force, because when it is applied, it is 'distributed' equally in each of the points (either a tendon or a wire or a rope or something similar). The 128N resistance should be preserved for tendons that have the same diameter.

Therefore the correct answer is A.

3 0

2 years ago

if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?

LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

The complete question is written below:

In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of $1.80 m/s^{2}$ , it would go from rest to its top speed in 85.6 s.

a) What was the speed of the vessel?

b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute?

Calculate the answers in both meters per second and kilometers per hour

a) The average acceleration $a_{av}$ is expressed as:

$a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t}$ (1)

Where:

$a_{av}=1.80 m/s^{2}$

$\Delta V$ is the variation of velocity in a given time $\Delta t$ , which is the difference between the final velocity $V$ and the initial velocity $V_{o}=0$ (because it starts from rest).