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Ronch [10]
3 years ago
9

What happens to the motion of an object when the forces acting on it are balanced? A. The motion changes. B. The motion does not

change. C. The motion speeds up. D. The motion slows down.
Physics
2 answers:
dexar [7]3 years ago
8 0

D. The motion slows down. Because If they are two forces putting force on the opposite sides, then the object would start to balance out and slow down

S_A_V [24]3 years ago
4 0

Question: What happens to the motion of an object when the forces acting on it are balanced?

Choices:

A. The motion changes.

B. The motion does not change.

C. The motion speeds up.

D. The motion slows down.

Answer: <u>D) The motion slows down when a motion of an object forces acting on the balance</u>.

<em>Hope this helps!.</em>

<em>~~~~~~~~~~~</em>

<em>~A.W~ZoomZoom44</em>

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Which statement describes the kinetic energy of a particle?
worty [1.4K]
Kinetic energy has nothing to do with anything other than motion of the particle.
When a particle with velocity v collides another particle(suppose it is at rest for simplication), assuming that there is perfectly elastic collision between them, the velocity of particle which was at rest becomes mv/M ( assuming mass of particle in motion to be m and at rest to be M) from convervation of linear momentum. And all this transfer of energy happens in a fraction of seconds which is not visible to naked eyes.

Hence 1st option is correct!
5 0
3 years ago
Plz answer brainliest if right!
AleksandrR [38]

Answer: it is D. it is the only possible answer. use the process of elimination. which answers make sense?

4 0
3 years ago
A table tennis ball has a mass of about 2.45 g. Suppose the ball is hit across the table with a speed of 4.0 m/s. What is it’s k
cluponka [151]

Answer:

0.0196 j

Explanation:

i) The formula for kinetic energy is as follows: 0.5*m*v^2

ii) Since we have all the values all that's left is to plug them into the equation

iii) First, WE MUST, Convert grams into kgs as this is the SI unit of mass so 2.45/1000

iv) All that's left now is to plug it into the equation so:

0.5* (s.45/1000)*(4^2)

v) Lastly we add the unit joules at the end as we're talking about energy

Hope this was useful! :)

3 0
2 years ago
What is the efficiency (w/qh) of an ideal carnot heat engine operating between a hot region at t= 400 k and a cold one at t= 300
Vinvika [58]
The efficiency of an ideal Carnot heat engine can be written as:
\eta = 1-  \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the temperature of the cold region
T_{hot} is the temperature of the hot region

For the engine in our problem, we have T_{cold}=300 K and T_{hot}=400 K, so the efficiency is
\eta= 1 - \frac{300 K}{400 K}=0.25
4 0
3 years ago
A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls c
Dafna11 [192]

Answer:

8.3m/s

Explanation:

Given parameters:

mass of clay ball  = 5kg

Speed of clay ball  = 25m/s

mass of clay ball at rest  = 10kg

speed of clay ball at rest  = 0m/s

Unknown:

Velocity after collision  = ?

Solution:

 Since the balls stick together, this is an inelastic collision:

   m1v1 + m2v2  = v(m1 + m2)

  5(25) + 10(0)  =  v (5 + 10)

         125 = 15v

           v  = 8.3m/s

7 0
3 years ago
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