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Ronch [10]
3 years ago
9

What happens to the motion of an object when the forces acting on it are balanced? A. The motion changes. B. The motion does not

change. C. The motion speeds up. D. The motion slows down.
Physics
2 answers:
dexar [7]3 years ago
8 0

D. The motion slows down. Because If they are two forces putting force on the opposite sides, then the object would start to balance out and slow down

S_A_V [24]3 years ago
4 0

Question: What happens to the motion of an object when the forces acting on it are balanced?

Choices:

A. The motion changes.

B. The motion does not change.

C. The motion speeds up.

D. The motion slows down.

Answer: <u>D) The motion slows down when a motion of an object forces acting on the balance</u>.

<em>Hope this helps!.</em>

<em>~~~~~~~~~~~</em>

<em>~A.W~ZoomZoom44</em>

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A speeding car collides with an unlucky bug flying across the road. Which explains why the impact doesn’t equally damage the car
velikii [3]
The bug was a lot smaller than the car, that's for sure. The car is bigger and sturdier, while the bug is smaller and frail. The bug is so frail, that rather that putting a dent in the car, it splatters all over the car. The bug is very damaged (obviously), while the car just needs a good wash.
8 0
3 years ago
A planet's moon travels in an approximately circular orbit of radius 7.0 ✕ 10⁷ m with a period of 6 h 38 min. Calculate the mass
natka813 [3]

Answer:

3.56×10²⁶ Kg.

Explanation:

Note: The gravitational force is acting as the centripetal force.

Fg = Fc........................... Equation 1

Where Fg = gravitational Force, Fc = centripetal force.

Recall,

Fg = GMm/r²......................... Equation 2

Fc = mv²/r............................. Equation 3

Where M = mass of the planet, m = mass of the moon, r = radius of the orbit and G = Universal gravitational constant.

Substituting equation 2 and 3 into equation 1

GMm/r² = mv²/r

Simplifying the equation above,

M = v²r/G .............................. Equation 4.

The period of the moon in the orbit

T = 2πr/v

Making v the subject of the equation,

v = 2πr/T............................. Equation 5

where r = 7.0×10⁷ m, T = 6 h 38 min = (6×3600 + 38×60) s = (21600+2280) s

T = 23880 s, π = 3.14

v = (2×3.14×7.0×10⁷ )/23880

v = 18409 m/s

Also Given: G = 6.67×10⁻¹¹ Nm²/kg²

Also substituting into equation 4

M = 18409²×7.0×10⁷ /(6.67×10⁻¹¹)

M = 3.56×10²⁶ Kg.

Thus the mass of the planet =  3.56×10²⁶ Kg.

5 0
3 years ago
Determine the identity of an unknown element X using the given table and following clues: I) Element X is a solid II) Element X
klasskru [66]
The answer is calcium. I just did it and it was correct
6 0
2 years ago
Read 2 more answers
During a football game, a receiver has just caught a pass and is standing still. Before he can move, a tackler, running at a vel
zmey [24]

Answer:

Mass of receiver is 92 kg        

Explanation:

We have given mass of tackler m_1=100kg

Let the mass of receiver is m_2kg

When tackler moving alone velocity is v_i=4.8 m/sec

And when tackler and receiver is together velocity is v_f = 2.5 m/sec

So from conservation of momentum

m_1v_i=(m_1+m_2)v_f

100\times 4.8=(100+m_2)\times 2.5

2.5m_2+250=480

2.5m_2=230

m_2=92kg

So mass of receiver is 92 kg

4 0
3 years ago
1. A double-slit experiment is set up using red light (l = 701 nm). A first order bright fringe is seen ata given location on a
Luba_88 [7]

Answer:

1)  λ = 467.3 10⁻⁹ m = 467.3 nm

2) Δy = 2.9 10⁻³ m

Explanation:

1) The interference experiment is described by the expression

      .d sin θ = m λ

It indicates that the wavelength is λ= 701 mn = 701 10⁻⁹ m and we have a first-order interference whereby m = 1, let's find the angle for which it occurs

      d sin θ = m λ

     d sin σ = λ₁                  (1)

We are asked to find the wavelength so that destructive interference occurs at this same point, which is described by

       d sin θ = (m + ½) λ        (2)

In this case also m = 1

We substitute 1 in 2

     λ₁ = (1 + ½) λ

     λ = λ₁ /1.5

Let's calculate

     λ = 701 10⁻⁹ /1.5

     λ = 467.3 10⁻⁹ m = 467.3 nm

2) In this new experiment we must find the distance to each strip

     Let's use trigonometry

        tan θ = y / x

Furthermore, the angles in these experiments are very small, so we can approximate the tangent to the sine

     tan θ = sin θ / cos θ = sin θ = y / x

We substitute

       d y / x = m λ

In this case m = 2

     y₁ = m λ x / d

     y₁ = 2 692 10⁻⁹ 2 / 0.1 10⁻³

     y₁ = 2.768 10⁻² m

For the other wavelength the interference is the third order m = 3

      y₂ = 3 413 10⁻⁹ 2 / 0.1 10⁻³

      y₂ = 2.478 10⁻² m

The distance between these two stripes is

    Δy = y₁ - y₂

    Δy = (2,768 - 2,478) 10⁻²

    Δy = 2.9 10⁻³ m

3 0
2 years ago
Read 2 more answers
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