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SIZIF [17.4K]
3 years ago
9

We’re measuring the velocity, so that we can find the change in kinetic energy. Where should you place the photogate to measure

the cart’s velocity? Briefly explain your reasoning.
Physics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

minimum two photogate

Explanation:

The photogate allows us to activate the measurement of time, so we must place at least two of them, one at the beginning of the movement to measure the initial time and another at the end of the movement to measure the final time, of course we must have measured the distance. This gives us the average speed between the two photocells

For measurements with more changes curves, slopes, one photogate must be placed at the beginning of the curve or slope and another at the end.

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Why the reflected rays for a rough surface do not result in the formation of an image.
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Answer:

this is because the light rays get reflected irregularly

Explanation:

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2 years ago
Which one is the answer
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translucent

Explanation:

you can see light coming thru but u cant see thru the glass.

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2 years ago
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You leave your home at 1pm. At 3pm, you are 100 km east of your house. What was your average velocity in km/hr
Rasek [7]

Answer:

50km/h

Explanation:

Average velocity = change in distance (or distance travelled) divided by/ the change in time (or time taken.)

The change in distance has been given as 100km.

The change in time is 3pm-1pm = 2 hours.

Therefore the average velocity was 100/2 = 50km/h (to the east).

Hope this helped!

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2 years ago
If the mass of an object is doubled, its gravitational force will:
tankabanditka [31]
Increase because the mass of an object aligns with its weight
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3 years ago
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Two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 9.8 m above the ground a
xenn [34]

Answer:

Time = 0.55 s

Height = 8.3 m

Explanation:

The ball is dropped and therefore has an initial velocity of 0. Its acceleration, g, is directed downward in the same direction as its displacement, h_b.

The dart is thrown up in which case acceleration, g, acts downward in an opposite direction to its displacement, h_d. Both collide after travelling for a time period, t. Let the height of the dart from the ground at collision be h_d and the distance travelled by the ball measured from the top be h_b.

It follows that h_d+h_b=9.8.

Applying the equation of motion to each body (h = v_0t + 0.5at^2),

Ball:

h_b=0\times t + 0.5\times 9.8t^2 (since v_{b0} =0.)

h_b=4.9t^2

Dart:

h_d=17.8\times t - 0.5\times9.8t^2 (the acceleration is opposite to the displacement, hence the negative sign)

h_d=17.8\times t - 4.9t^2

But

h_b+h_d =9.8

17.8\times t - 4.9t^2+4.9t^2 =9.8

17.8\times t = 9.8

t = 0.55

The height of the collision is the height of the dart above the ground, h_d.

h_d=17.8\times t - 4.9t^2

h_d=17.8\times 0.55 - 4.9\times(0.55)^2

h_d=9.79 - 1.48225

h_d=8.3

8 0
3 years ago
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