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2 years ago

Which of the following is not found in dry air?

Physics

1 answer:

tensa zangetsu [6.8K]2 years ago

5 0

C.water vapor i hope i helped

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(P.E) Physical Activity and Fitness.......,,,

Greeley [361]

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1. resting heart rate

2. overload

3. workout

4. specificity

5. cool-down

6. progression

7. warm-up

8. the last one can only be instance, but there was a typo on the paper.

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2 years ago

What time period did fish develop

marysya [2.9K]

Answer:

They developed during the Cambrian time period, which was around 530 million years ago.

Explanation:

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3 years ago

A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s

Naddika [18.5K]

Answer:

A) the maximum acceleration the boulder can have and still get out of the quarry

B) how long does it take to be lifted out at maximum acceleration if it started from rest

Explanation:

let +y is upward. look below at the free body diagram. the mass M refers to the combined mass of the boulder and chain.

the weight of the chain is: $w_{c} =m_{c} g$ and maximum tension is $T=2.50 m_{c} g=1.41*10^4N$

total mass and weight is :

$M =m_{c}+ m_{b} =740kg+550kg=1290 kg$

$w_{M} =1.2650*10^4N$

∑ $F_{y} =ma_{y}$

$T-M_{g} =Ma_{y}$

$a_{y} =(t-M_{g} )/M=(2.50m_{c} -M_{g} )/M=(2.50.550kg-1290kg)(9.8m/s^2)/1290kg$

$=0.645m/s^2$

maximum acceleration

$a_{y} =0.645m/s^2\\\\y-y_{0} =119m\\v_{0y} =0$

using $y-y_{0} =v_{oy} t+1/2(a_{y} )t^2$

to solve for t

$t=\sqrt{2(y-y_{0} )/a_{y} }$

$t=\sqrt{2(119m)/0.645m/s^2} =19.20s$

6 0

3 years ago

Answer it pls!!!!!!!!!!!

Archy [21]

Answer:

Fractional error = 0.17

Percent error = 17%

F = 112 ± 19 N

Explanation:

Plug in the values to find the force:

F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N

Find the fractional error:

ΔF/F = Δm/m + 2Δv/v + Δr/r

ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5

ΔF/F = 0.17

Multiply by 100% to find the percent error:

ΔF/F × 100% = 17%

Solve for the absolute error:

ΔF = 0.17 × 112 N = 19 N

Therefore, the force is:

F = 112 ± 19 N

8 0

2 years ago

If a range hood removes contaminants at a flow rate of F liters of air per second, then the percent P of contaminants that are

podryga [215]

Explanation:

The given value of P is as follows.

P = 1.06F + 22.18, $10 \leq F \leq 70$

or, P' = 1.06

As p' is defined and non-zero. Hence, only critical points are boundary points.

For F = 10, the value of P will be calculated as follows.

P = $1.06 \times 10 + 22.18$

= 32.78

For F = 70, the value of P will be calculated as follows.

P = $1.06 \times 70 + 22.18$

= 96.38

Therefore, the minimum value of P is 32.78 and maximum value of P is 96.38.

3 0

2 years ago