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valentinak56 [21]
3 years ago
10

Which of the following is not found in dry air?

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0
C.water vapor i hope i helped

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Describe what we may observe from Earth regarding the moon’s revolution around the earth and its rotation
slava [35]

When we look at the moon from the Earth, we always see the same light spots, dark spots, and shapes. It never changes. There could be two possible reasons for this:

-- The moon is a flat disk with some markings on it, and one side of it always faces the Earth.

-- The moon is a round ball with some markings on it, and one side of it always faces the Earth.

Either way, since the same side always faces the Earth, the only way that can happen is if the moon's revolution around the Earth and rotation on its axis both take EXACTLY the same length of time.

Even if they were only one second different, then we would see the moon's whole surface over a long period of time. But we don't. So the moon's rotation and revolution must be EXACTLY locked to the same period of time.

4 0
3 years ago
Atoms with the same atomic number but different atomic mass are called
Alexxx [7]
<span>Atoms with the same atomic number but different atomic mass are called:

<span>Isotopes</span>
</span>
4 0
3 years ago
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A bus is moving with an acceleration of 4 m/s^2. If it was initially at rest,
shusha [124]
Probably b) 6 m/s
Not sure
6 0
3 years ago
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At what rate must a cylindrical spaceship rotate if occupants are to experience simulated gravity of 0.50 gg? Assume the spacesh
Svetradugi [14.3K]

Answer:

The time needed is T  = 16.8 s

Explanation:

From the question we are told that

      The magnitude of the stimulated acceleration due gravity is  a  =  0.5 g

        The diameter of the spaceship is  d =  35m

       

Generally the force acting on the spaceship is  

       F  =  ma

Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

      F  = \frac{mv^2}{r}

Thus  

       ma  =  \frac{mv^2}{r}

=>    \frac{v^2}{r}  =  a

      Generally the speed of this spaceship is mathematically represented as

      v =  \frac{2 \pi}{T}

=>    v^2  =   [\frac{2\pi}{T}] ^2

=>     \frac{\frac{4\pi^2 r^2}{T^2} }{r}  = 0.5g

=>       \frac{4 \pi^2 r }{T^2} =  0.5 g

=>         T  = \sqrt{ \frac{4\pi^2 r}{0.5g}}

substituting values

          T  = \sqrt{ \frac{4* (3.142)^2 *(35)}{0.5 * 9.8}}

         T  = 16.8 s

4 0
3 years ago
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An object has a mass of 2,000kg. what is its weight on earth? show your work​
artcher [175]

Answer:

F=m*g is the formula and the answer is 19,620 kg

Explanation:

Since the formula is F=m*g and Earth's gravity is 9.81 m/s^2 all you need to do is multiply 2,000 by 9.81

6 0
3 years ago
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