It would not. Imagine four forces equal in magnitude but opposite in direction (e.g. north, east, south, and west). If these forces were to double in magnitude they would still have the same magnitude, meaning the net force is still equal to zero.
Answer:
(a) 41.75m/s
(b) 4.26s
Explanation:
Let:
Distance, D = 89m
Gravity, = 9.8 m/
Initial Velocity, = 0m/s
Final Velocity, = ?
Time Taken, = ?
With the distance formula, which is
D = +
and by substituting what we already know, we have:
89 = ×9.8×
With the equation above, we can solve for :
Now that we have solved , we can use the following velocity formula to solve for :
, where is also equals to , so we have
By substituting , , and ,
We have:
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\Delta L= \alpha L_0 (T_f-T_i)
= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)
= -0.00225 m
New length = L + ΔL
= 1.25 m + (-0.00225 m)
= 1.248
So your answer is B.
It means the speed of the object is increasing
and
there is a positive acceleration in the direction of the velocity
hence
there is a force acting on the object, in the direction of the velocity