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Amiraneli [1.4K]
3 years ago
13

A transformation of ΔSTV results in ΔUTV. Which transformation maps the pre-image to the image?

Physics
2 answers:
Blizzard [7]3 years ago
6 0

Notice that TV is in the original triangle and in the image. That means that we are looking for a transformation where this segment remains fixed (doesn’t move) which is the case when doing a reflection. A reflection over the line segment TV would leave that segment unchanged. Think of having the triangle iba page and picking p vertex S swinging it over TV and having it land on the other side. TV the line of reflection remains fixed while S moves to a new point here called U.

user100 [1]3 years ago
6 0

Answer:

reflection on ed 2020

Explanation:

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A spaceship hovering over the surface of Venus drops an object from a height of 17 m. How much longer does it take to reach the
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1.96s and 1.86s. The time it takes to a spaceship hovering the surface of Venus to drop an object from a height of 17m is 1.96s, and the time it takes to the same spaceship hovering the surface of the Earth to drop and object from the same height is 1.86s.

In order to solve this problem, we are going to use the motion equation to calculate the time of flight of an object on Venus surface and the Earth. There is an equation of motion  that relates the height as follow:

h=v_{0} t+\frac{gt^{2}}{2}

The initial velocity of the object before the dropping is 0, so we can reduce the equation to:

h=\frac{gt^{2}}{2}

We know the height h of the spaceship hovering, and the gravity of Venus is g=8.87\frac{m}{s^{2}}. Substituting this values in the equation h=\frac{gt^{2}}{2}:

17m=\frac{8.87\frac{m}{s^{2} } t^{2}}{2}

To calculate the time it takes to an object to reach the surface of Venus dropped by a spaceship hovering from a height of 17m, we have to clear t from the equation above, resulting:

t=\sqrt{\frac{2(17m)}{8.87\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{8.87\frac{m}{s^{2} } } }=1.96s

Similarly, to calculate the time it takes to an object to reach the surface of the Earth dropped by a spaceship hovering from a height of 17m, and the gravity of the Earth g=9.81\frac{m}{s^{2}}.

t=\sqrt{\frac{2(17m)}{9.81\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{9.81\frac{m}{s^{2} } } }=1.86s

8 0
3 years ago
Read 2 more answers
A teacher did an experiment to show the movement of particles in solids, liquids, and gases. The experimental set-up is shown be
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Whereas in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Hence, gases are able to expand more rapidly as compared to liquids.

Thus, we can conclude that out of the given options solid = low; liquid = medium; gas = high, combination of the state of matter and the corresponding dryer speed is correct.

8 0
3 years ago
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