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frez [133]
3 years ago
10

What is the efficiency (w/qh) of an ideal carnot heat engine operating between a hot region at t= 400 k and a cold one at t= 300

k?
Physics
1 answer:
Vinvika [58]3 years ago
4 0
The efficiency of an ideal Carnot heat engine can be written as:
\eta = 1-  \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the temperature of the cold region
T_{hot} is the temperature of the hot region

For the engine in our problem, we have T_{cold}=300 K and T_{hot}=400 K, so the efficiency is
\eta= 1 - \frac{300 K}{400 K}=0.25
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Answer:

18 m

Explanation:

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Solving for the average velocity. avg v

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See attachment

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think of two school rules and briefly describe how these rules help protect health and why its important to follow them.
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Answer:

x ≤ 3.6913 m

Explanation:

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If we take torques around the left end as follows

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⇒   - (Mrod*g)*(L/2) - (Mman*g)*x + Tmax*Sin 30º*L = 0

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3 years ago
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