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4 years ago

Circumference 17 inches Use 3.14 for pi

Mathematics

2 answers:

Trava [24]4 years ago

7 0

Answer:

53.4 m

Step-by-step explanation:

please name me branliet i really need it

Marysya12 [62]4 years ago

5 0

Answer: (BRAINLIEST PLEASE)

53.4 m

Step-by-step explanation:

<h3><u><em>Write down the formula for finding the circumference of a circle using the diameter. The formula is simply this: C = πd. In this equation, "C" represents the circumference of the circle, and "d" represents its diameter. That is to say, you can find the circumference of a circle just by multiplying the diameter by pi.</em></u></h3>

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Factorising quadratics <br><br> All questions please to be completed. I’m stuck.

Alex777 [14]

Answer:

1. (x +1)(x - 1)

2. (x+5)(x-5)

3. (x+12)(x-12)

4. (x+14)(x-14)

5. (x+5)(x-7)

Step-by-step explanation:

The first 4 expressions can be factored with the difference of squares type of factoring.

For #5, the odd one out is (x+5)(x-7) because it isn't a factor of any of the standard form equations, while the others are

5 0

4 years ago

10 points, thank you in advance :)

Sophie [7]

Answer:

-3 + 10i

sqrt-100 = sqrt100i

sqrt100 = 10

So,

-3 + 10i

8 0

3 years ago

what is 4.6 rounded ? what is 0.5 rounded? what is 4.5 rounded? what is 5.5 rounded? what is 0.6 rounded?

mr Goodwill [35]

Answer:

4.6 is 5 , 0.5 is 1, 4.5 is 5, 5.5 is 6 and 0.6 is 1

Step-by-step explanation:

If the second digit after the decimal is 5 or high you round it up

5 0

3 years ago

Read 2 more answers

A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

3 years ago

Find the area of each composite figure. Use 3.14 for π. Round to the nearest tenth if necessary. Whats the correct label?

GuDViN [60]

Step-by-step explanation:

Square= bh

Square= 2×2=

half-circle = 1/2Pi*r×r

half-circle 2 = 1/2Pi*r×r

We would put 1/2 for the half-circle because its half of a circle. And we square it because where finding area. The middle is square, and the two up top is half a circle. Hope that helps :D

8 0

3 years ago

Read 2 more answers