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Sati [7]
3 years ago
9

Enter the value of C when the expression 21.2x+c is equivalent to 5.3(4x-2.6)

Mathematics
2 answers:
vichka [17]3 years ago
8 0
Make the equations equal to each other to find x. 

21.2x+c=5.3(4x-4.6)

Now distribute. 

21.2x+c=21.2x-24.38

So c= -24.38
likoan [24]3 years ago
4 0
Make the equations equal to each other to find x. 

21.2x+c=5.3(4x-4.6)

Now distribute. 

21.2x+c=21.2x-24.38

So c= -24.38
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How do I solve this problem?
Andrews [41]

so the line is dog so we know the full line is 60 units long. The 2 parts (do and og) add up to the full length so we can make the equation:

(4x-3)+(2x+21)=60

6x+18=60

6x=42

x=7

if you need to fine do or og, just plug in x to its equation

6 0
3 years ago
What is the written form for (8,8)
Sav [38]

Answer:

81 900 000 000 000 is 8.19 × 10¹³

Step-by-step explanation:

Write the first number 8.

Add a decimal point after it: 8.

Now count the number of digits after 8. There are 13 digits.

So, in standard form: 81 900 000 000 000 is 8.19 × 10¹³

5 0
3 years ago
15% of 20 is ____ find the percentage of the number
Aliun [14]
The answer is 3, just do 20*0.15 (covert 15% into a decimal).
6 0
3 years ago
Read 2 more answers
In the textile industry, a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material.
Naily [24]

Answer:

b. Binomial distribution.

Step-by-step explanation:

As a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material which shows that only two possible outcomes with fixed number of trials are present here, so the probability distribution that has the greatest chance of applying to this situation is a binomial distribution that summarizes the possibility that a value will take one of two independent values under a provided set of parameters.

5 0
3 years ago
For the function given state the period f(t) =6sin(3t-pi/6)-1
lapo4ka [179]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now, with that template in mind, let's take a peek at yours

\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}
8 0
4 years ago
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