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3 years ago

How do I solve this problem?

Mathematics

1 answer:

Andrews [41]3 years ago

6 0

so the line is dog so we know the full line is 60 units long. The 2 parts (do and og) add up to the full length so we can make the equation:

(4x-3)+(2x+21)=60

6x+18=60

6x=42

x=7

if you need to fine do or og, just plug in x to its equation

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For her birthday, Monica can invite 6 of her 15 student friends to join her at a theme park. If she chooses to invite friends at

svlad2 [7]

Answer:

B. 1 out of 5,005

Step-by-step explanation:

Given

Number of Friends = 15

Required

Probability of selecting 6 friends

The first step is to calculate the number of ways 6 friends can be selected

The keyword in the above statement is selection;

This implies combination;

The number of ways is calculated as follows;

$\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 15 and r = 6

$\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}$

becomes

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{(15-6)!6!}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{9!6!}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10 * 9!}{9! *6 * 5 * 4 * 3 * 2 * 1}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10}{6 * 5 * 4 * 3 * 2 * 1}$

$\left[\begin{array}{c}15&6&\end{array}\right] = \frac{3603600}{720}$

$\left[\begin{array}{c}15&6&\end{array}\right] =5005$

Hence, there are 5005 ways of selecting 6 from 15 friends

Since, there's only one way of selecting the 6 named friends

Then, the probability is 1 out of 5,005

3 0

3 years ago

Laura earns $ 255 by working 20 hours each week .

Lostsunrise [7]

You will have to figure out the last equation but here is the rest:

8 0

4 years ago

Clarence works at least 5 hours but not more than 7 hours. he earns $11.60 per hour. the function f(t)=11.6t represents the amou

Pavel [41]

Function: f(t) = 11.6 t

Restrictions: 5 ≤ t ≤ 7

Domain: possible values of t: all real values between 5 and 7 inclusive

Range: possible values of f(t): from 11.6 * 5 to 11.6 *7 = from 58 to 81.2, inclusive.

Answer:

the practical domain is all real numbers from 5 to 7, inclusive. and the practical range is all real numbers from 58 to 81.2

4 0

3 years ago

Read 2 more answers

3w+1≥19 Solve the inequality

Rufina [12.5K]

Step-by-step explanation:

group like terms

$3w \geqslant 19 - 1$