Answer:
A: (2, 11).
Step-by-step explanation:
For an ordered pair to be a solution of an equation, the ordered pair must "fit".
A: (2, 11).
11 = 3(2) + 5
11 = 6 + 5
11 = 11
So, (2, 11) is a solution.
B: (3, 13).
13 = 3(3) + 5
13 = 9 + 5
13 = 14
Since 13 is not the same thing as 14, (3, 13) is not a solution.
Since A works but B doesn't, choices C and D are both eliminated. A is your answer.
Hope this helps!
1. <span>Let n = Tom's weight in pounds.
m=</span>Jim's weight in pounds.
m=n - 30
m+n=210
We solve this by substitution:
(n - 30)+n=210
2n-30=210
2n=210+30
2n=240
n=120 pounds weighs Tom
m=120-30=90 pounds weighs Jim
2. Let n = the number of boys.
g = the number of girls.
n+g=19
g=n+5
By substitution:
n+(n+5)=19
2n+5=19
2n=19-5
2n=14
n=14:2
n=7 boys
g=7+5=12 girls
3. Let n = the<span> shortest side</span> of the triangle
each of the two sides that are equal in length=2n
<span>The perimeter=n+2n+2n=36 inches</span>
5n=36
n=7.2 inches is the shortest side of the triangle
2*7.2=14.4 inches is each of the two sides that are equal in length
Answer:
LCM of 6 and 15 by Listing Multiples
Step 2: The common multiples from the multiples of 6 and 15 are 30, 60, . . . Step 3: The smallest common multiple of 6 and 15 is 30.
Which of the following did you include in your response?
Javier did not raise the coefficients to the third power
When Javier raised (x^1)^3 to the third power, he wrote that x^4, but it equals x^3.
In the last step, Javier divided the exponents. He should have used the quotient of powers property and subtracted them.