The volume of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.45 oun
ces and a standard deviation of 0.30 ounce. The company receives complaints from consumers who actually measure the amount of soda in the cans and claim that the volume is less than the advertised 12 ounces. What proportion of the soda cans contain less than the advertised 12 ounces of soda?
Given : The volume of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.45 ounces and a standard deviation of 0.30 ounce.
i.e. and
Let x denotes the volume of soda a dispensing machine pours into a 12-ounce can.
Then, the proportion of the soda cans contain less than the advertised 12 ounces of soda will be :-
Hence, the proportion of the soda cans contain less than the advertised 12 ounces of soda = 0.0668
He will spend $66.3 because 78 times 15/100 (which is 15%) is 11.7, and since he reduces the food you will have to subtract 11.7 from $78, to get $66.3
This is a fairly simple problem meaning it has very few steps. If it makes 75 pages in 5 minutes you need to find out what the PPM or Page Per Minute is.
To find that you simply divide 75 by 5 and get 15 and in one minute the printer prints 15 pages.
