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3 years ago

Which layer of the atom sphere contacts the surface of earth

1 answer:

4 0

The troposphere is the layer of the atmosphere which contacts the surface of the Earth. This layer is 0 to 12 km (0 to 7 miles).

Faith xoxo

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Expand your answer for me plz.

daser333 [38]

kinetic energy when the pitcher has thrown it or when one of the other players has thrown the ball. The baseball also has kinetic energy when the batter hits the ball. when you catch the ball it is potential energy.

5 0

3 years ago

Read 2 more answers

Which of the following statements apply to electric charges?

Gre4nikov [31]

Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

When a positively charged rod is brought close to a positively charged object, the rod and the object will repel.

6 0

3 years ago

7. A 1300 kg car starts at rest and rolls down a hill from a height of 10.0 m. It then moves across a level (frictionless) surfa

makkiz [27]

Answer:

0.505 m

Explanation:

From the question,

The kinetic energy of the car = energy stored in the spring

1/2mv² = 1/2ke²...................... Equation 1

Where m = mass of the car, v = velocity of the car, k = spring constant of the car, e = extension/compression

make e the subject of the equation

e = v√(m/k)............... Equation 2

We can calculate the value of v, by applying,

v² = u²+2gH...................... Equation 3

Where u = initial velocity of the car, H = height of the car, g = acceleration due to gravity.

Given: u = 0 m/s (from rest), H, 10 m, g = 9.8 m/s²

Substitute into equation 2

v² = 2(10×9.8)

v² = 196

v = √196

v = 14 m/s

Also given: m = 1300 kg, e = 1.0×10⁶ N/m =1000000 N/m

Substitute into equation 2

e = 14√(1300/1000000)

e = 14√(0.00013)

e = 14(0.036)

e = 0.505 m

Hence the maximum distance of the spring is compressed = 0.505 m

5 0

3 years ago

When not in a vacuum, what force causes objects in freefall to fall at different speeds??

Deffense [45]

Hi,

My best answer would be Gravity. Is it a multiple choice question? Or is it an essay question.

4 0

4 years ago

A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s,

Andreyy89

The final position of the car is 385 m.

Explanation:

We know the formula :

s = $ut +$ $\frac{1}{2} at^{2}$

where,

s = distance

u = initial velocity = 5.1 m/s

t = time taken = 14 sec

a = acceleration = 3.2 m/ $s^{2}$

Solving:

s = 5.1* 14 + $\frac{1}{2}$ * 3.2 * $14^{2}$

∴ s = 385 m

Hence the final position of the car is 385 m.

3 0

3 years ago