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Studentka2010 [4]
4 years ago
12

An AC voltage source of amplitude 10V is supplied across an inductor and a resistor wired in series. The voltage amplitude acros

s the inductor is 5V. The voltage amplitude across the resistor is closest to:___________.
Physics
1 answer:
marin [14]4 years ago
4 0

Answer:

8.66 V

Explanation:

Vo = 10 v

VL = 5 V

VR = ?

According to the equation of LR circiut

V_{0}^{2}=V_{R}^{2}+ V_{L}^{2}

10 x 10 = VR² + 5 x 5

100 - 25 = VR²

VR² = 75

VR = 8.66 V

Thus, the voltage amplitude across the resistor is 8.66 v.

Explanation:

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An object kept in front of lens, which is thick at the edges, produces a _________,
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4 0
3 years ago
Consult Interactive Solution 10.37 to explore a model for solving this problem. A spring is compressed by 0.0647 m and is used t
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Answer:

\omega=32.14\ rad/s

Explanation:

Given that,

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Speed of the object, v = 2.08 m/s

To find,

Angular frequency of the object.

Solution,

We know that the elation between the amplitude and the angular frequency in SHM is given by :

v=\omega\times A

A is the amplitude

In case of spring the compression in the spring is equal to its amplitude

\omega=\dfrac{v}{A}

\omega=\dfrac{2.08\ m/s}{0.0647\ m}

\omega=32.14\ rad/s

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4 0
3 years ago
In the parallel spring system, the springs are positioned so that the 37 N weight stretches each spring equally. The spring cons
Reptile [31]

Answer:

x = 5.29 m

Explanation:

given,

weight of stretch = 37 N

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right hand spring constant(k₂)= 4.3 N/ cm

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F = F₁ + F₂

F = k₁x + k₂x

F = (k₁+ k₂)x

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7 x = 37

x = 5.29 m

3 0
3 years ago
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