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Studentka2010 [4]
3 years ago
12

An AC voltage source of amplitude 10V is supplied across an inductor and a resistor wired in series. The voltage amplitude acros

s the inductor is 5V. The voltage amplitude across the resistor is closest to:___________.
Physics
1 answer:
marin [14]3 years ago
4 0

Answer:

8.66 V

Explanation:

Vo = 10 v

VL = 5 V

VR = ?

According to the equation of LR circiut

V_{0}^{2}=V_{R}^{2}+ V_{L}^{2}

10 x 10 = VR² + 5 x 5

100 - 25 = VR²

VR² = 75

VR = 8.66 V

Thus, the voltage amplitude across the resistor is 8.66 v.

Explanation:

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Explanation:

You solve these kinetic energy, potential energy problems by using the fact P.E.+ K.E. = a constant as long as friction is ignored.

PEi = 0 in this case

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