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Studentka2010 [4]
4 years ago
12

An AC voltage source of amplitude 10V is supplied across an inductor and a resistor wired in series. The voltage amplitude acros

s the inductor is 5V. The voltage amplitude across the resistor is closest to:___________.
Physics
1 answer:
marin [14]4 years ago
4 0

Answer:

8.66 V

Explanation:

Vo = 10 v

VL = 5 V

VR = ?

According to the equation of LR circiut

V_{0}^{2}=V_{R}^{2}+ V_{L}^{2}

10 x 10 = VR² + 5 x 5

100 - 25 = VR²

VR² = 75

VR = 8.66 V

Thus, the voltage amplitude across the resistor is 8.66 v.

Explanation:

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The voltage entering a transformer’s primary winding is 120 volts. The primary winding is wrapped around the iron core 10 times.
loris [4]
<u>Answer</u>

 48 Volts  

<u>Explanation</u>
The question can be solve using the turn rule of a transformer that states;

Np/Ns = Vp/Vs
Where Np ⇒ number of turns in the primary coil.
            Ns ⇒number of turns in the seconndary coil
            Vp ⇒ primary voltage
             Vs ⇒secondary voltage

Np/Ns = Vp/Vs

10/4 = 120/Vp

Vp = (120 × 4)/10

      = 480/10
      = 48 Volts  

 

5 0
4 years ago
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3 years ago
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Answer:

I believe its C

Explanation:

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What are light years actually? answer in brief
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Waves are observed passing under a dock. Wave crests are 8.0 meters apart. The time for a complete wave to pass by
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Answer:

Option D

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Explanation:

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Essentially, what we wanted is velocity

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