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klio [65]
3 years ago
9

Create a division formula.

Computers and Technology
1 answer:
baherus [9]3 years ago
4 0

Answer:

=(A4+B4+C4+D4+E4)/5

Explanation:

If we want to have the average of the passengers, first we must sum all the revenue and then divide it with passenger quantity.

In this particular example, I made the formula with 5 passengers, I sum the 5 revenues and then I divide with 5 passengers if there are more passengers we must sum all of them, and divided all of them, for example:

=(A4+B4+C4+D4+E4+F4)/6

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Write function d2x() that takes as input a nonnegative integer n (in the standard decimal representation) and an integer x betwe
Rufina [12.5K]

Answer:

The function in Python is as follows:

def d2x(d, x):

   if d > 1 and x>1 and x<=9:

       output = ""

       while (d > 0):

           output+= str(d % x)

           d = int(d / x)

       output = output[::-1]

       return output

   else:

       return "Number/Base is out of range"

Explanation:

This defines the function

def d2x(d, x):

This checks if base and range are within range i.e. d must be positive and x between 2 and 9 (inclusive)

   if d >= 1 and x>1 and x<=9:

This initializes the output string

       output = ""

This loop is repeated until d is 0

       while (d > 0):

This gets the remainder of d/x and saves the result in output

           output+= str(d % x)

This gets the quotient of d/x

           d = int(d / x) ----- The loop ends here

This reverses the output string

       output = output[::-1]

This returns the output string

       return output

The else statement if d or x is out of range

<em>    else:</em>

<em>        return "Number/Base is out of range"</em>

<em />

4 0
3 years ago
Question 1:
Julli [10]

Answer:

Following are the code to the given question:

#include<iostream>//header file

#include<math.h>//header file

using namespace std;

int main()//main method

{

   long long x, x1, y, y1;//defining long variable

   int count=0,i,j;//defining integer variable

   cout<<"Enter a range for x coordinates: "<<endl;//print message        

   cin>>x>>x1;//input x and x1 value                          

   cout<<"Enter a range for y coordinates: "<<endl;//print message

   cin>>y>>y1; //input y and y1 value  

   for(i = x; i <= -x1; i++)//use nested loop that tests each coordinates                                        

   {

       for(j = y; j <= y1; j++)//use nested loop that tests each coordinates

       {

           if(((2*pow(i,2)) + abs(2*i*j) + pow(j,2)) == 10000)//use if that checks condition as per the given question

           {

               cout<<"There is a planet at "<<i<<", "<<j<<endl;//  print coordinates

               count++;//incrementing count variable value                                                    

           }

       }

   }

   cout<<"Total number of planets detected are: "<<count<<endl;//print count value

   return 0;

}

Explanation:

In this code, inside the main method long "x, x1, y, and y1" and integer "count, i, and j" type variable is declared that uses a long variable to input value from the user-end.

In the next step, two nested loops have defined that test each coordinate and define if block that checks condition as per the given question and use i, j, and count variable to print value with the message.

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