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cupoosta [38]
3 years ago
9

What is a male reproductive organ?

Chemistry
1 answer:
motikmotik3 years ago
6 0

Answer:

Organs of the male productive system are the scrotum, spermatic ducts, sex glands, and penis. They coinside to produce sperm, gametes, and semen.

Explanation:

I payed attention in health <3 nah jk I am an expert of all things man

<h2><u><em>xoxo, </em></u></h2><h2><u><em>your highness...</em></u></h2>
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What is the mass of calcium in 2.3•10^23 molecules of calcium phosphate
Katena32 [7]

Explanation:

N(Ca)=3×N(Ca₃(PO₄)₂)=

=3×2.3×10²³=6.9×10²³

6.02×10²³→40g

6.9×10²³→Xg

m(Ca)=X≈45.85g

3 0
3 years ago
If an atom contains one electron and one proton,will it carry any charge or not​
sertanlavr [38]

Answer:

no it will have no charge...it would be electrically neutral! because the number of protons and electrons are equal!

8 0
3 years ago
Read 2 more answers
Brainliest for an answer!
Degger [83]

The volume of H₂ : = 15.2208 L

<h3>Further explanation</h3>

Given

Reaction

2 As (s) + 6 NaOH (aq) → 2 Na₃AsO₃ (s) + 3 H₂ (g)

34.0g of As

Required

The volume of H₂ at STP

Solution

mol As (Ar = 75 g/mol) :

= mass : Ar

= 34 g : 75 g/mol

= 0.453 mol

From the equation, mol ratio As : H₂ = 2 : 3, so mol H₂ :

=3/2 x mol As

=3/2 x 0.453

= 0.6795

At STP, 1 mol = 22.4 L, so :

= 0.6795 x 22.4 L

= 15.2208 L

5 0
3 years ago
The energy of an electron in a multielectron atom is determined by
Wewaii [24]

Answer:

by principal quantum number (n) and azimuthal quantum number (l)

Explanation:

I used the web to answer so I'm not sure if this is right

5 0
3 years ago
A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif
slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})

where,

Q = heat absorbed by metal = 186.75 J

m_1 = Mass of metal= 19 g

T_1 = Initial  temperature of metal = 35^oC

T_2 =Final  temperature of metal = 175^oC

c = specific heat of metal= ?

186.75 J=19 g\times c\times (175^oC-35^oC)

c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}

c=0.0702J/g^oC

0.0702J/g°C the specific heat capacity of the metal.

6 0
3 years ago
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