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Sergeeva-Olga [200]
3 years ago
13

For what value of x is line a parallel to line b (9x+11)

Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

15

Step-by-step explanation:

124° + 9x + 11 = 180 ➡ 9x = 135° ➡ x = 15

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I don't understand number 6 please help
ycow [4]
X^-n = 1/x^n 
Your fraction becomes:
1/ {(m^5 t^2)(27m^6t^3)} now combine the powers in the denominator
1/ (27 m^11 t^5)
7 0
3 years ago
Read 2 more answers
A bakery can make 60 donuts in 15 donutes. What is the unit rate at which the bakery makes donuts.
maria [59]

Answer:

4 donuts per minute/(donutes is that a typo?)

Step-by-step explanation:

if a bakery can make 60 donuts in 15 minutes, that is 60 donuts/15 minutes.

to reduce this fraction, the top and bottom can be divided by 15 to get 4 donuts/1 minute.

7 0
3 years ago
How can you identify the y intercept on a graph?
Veseljchak [2.6K]

Answer:

Is there a graph that goes with this question by chance?

Step-by-step explanation:

8 0
2 years ago
A department store sold 62 shirts one day. All short-sleeved shirts cost $11.00 each and all long-sleeved shirts cost $17.00 eac
slava [35]

Answer:

a. Short-Sleeve = 35

b. Long-Sleeve = 27

Step-by-step explanation:

Given data:

Total shirts sold = 62

short sleeved cost = 11 each

Long sleeved cost = 17 each

Total receipts = 844

<em>Let the count of short sleeved be X  and Let the count of long sleeved be Y</em>

X + Y = 62 <em>(equation 1) from the total shirts sold</em>

11X + 17Y = 844 <em>(equation 2) from the total receipts</em>

<em>From equation 1</em>    X = 62 - Y <em>(Equation 3)</em>

<em>Substituting equation 3 into equation 2</em>

11(62 - Y) +17Y = 844

682 -11Y + 17Y = 844

-11Y + 17Y = 844-682

6Y = 162

Therefore Y = 27

<em>Substituting Y into equation 3</em>

X = 62 - Y

X = 62 - 27

X = 35

5 0
3 years ago
Read 2 more answers
2v^2-12 =-12v <br> Would really appreciate it loves❤️
Black_prince [1.1K]

For this case we have the following equation:

2v ^ 2-12 = -12v

Rewriting we have:

2v ^ 2 + 12v-12 = 0

Dividing by 2 to both sides of the equation:

v ^ 2 + 6v-6 = 0

We apply the quadratic formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

We have to:

a = 1\\b = 6\\c = -6

Substituting:

x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}

Thus, we have two roots:

x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}

ANswer:

x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}

7 0
3 years ago
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