Answer:
Step-by-step explanation:
Given the approximate demand function of night drink expressed as;
p^2+200q^2=177,
p is the price (in dollars) and;
q is the quantity demanded (in thousands).
Given
p = $7
q = 800
Required
dq/dp
Differentiating the function implicitly with respect to p shown;
2p + 400d dq/dp = 0
400q dq/dp = -2p
200qdq/dp = -p
dq/dp = -p/100q
substitute p and q into the resulting equation;
dq/dp = -7/100(800)
dq/dp = -7/80000
dq/dp = -0.0000875
This means that the rate of change of quantity demanded with respect to the price is -0.0000875
Just find the volume of a triangular prism.
volume=1/2*length*width*height.
Answer:

Step-by-step explanation:
To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:
![A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%261%261%261%5C%5C3%267%26-1%261%5Cend%7Barray%7D%5Cright%5D)
And the vector B is formed with the solution of each equation of the system:![b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C-3%5C%5C6%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called
.
![A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%266%261%261%5C%5C3%261%26-1%261%5Cend%7Barray%7D%5Cright%5D)
The value of y using Cramer's rule is:

Find the value of the determinant of each matrix, and divide:


Hi there! :)

4x + 5x + 12 = 6(x - 2)
Combine like terms and distribute the coefficient outside of the parenthesis:
9x + 12 = 6(x) + 6(-2)
9x + 12 = 6x - 12
Subtract 6x from both sides:
9x - 6x + 12 = 6x - 6x - 12
3x + 12 = -12
Subtract 12 from both sides:
3x + 12 - 12 = -12 - 12
3x = -24
Divide both sides by 3:
3x/3 = -24/3
x = -8.
Considering that 1 kilogram is equal to 1000 grams and he made 9 loaves of bread using 30 grams each time, that equates to 270 grams of olives. 1000 - 270 = 730. Your answer is 730 grams of olives remain. Hope this helped.