Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3
Answer:
I’m pretty sure 19 years old.
Step-by-step explanation:
Hope I could help
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Hey,
We can see here 2 of the angles are equal and the third one is a right angle right?
That means it is an isosceles triangle since they have 2 equel angles and a right anlgle.
Another feature of the isosceles triangle is that 2 sides are equal.
We are given one side is 5.5 right?
So the side BC has to be 5.5 or the side AB has to be 5.5
In isosceles triangles the side opposite to the 90 degree angle is the hypotenuse.This means it is the longest angle.
So it has to be AB which is equal to 5.5 since BC is the hypotenuse.
Hope this helps,Happy New Year
