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3 years ago

Find the exact area of the region bounded by two concentric circles with radii 10 inches and 6 inches.

2 answers:

6 0

Area of circle
A = pi r^2
A = pi(10^2 - 6^2)
bounded by both is 36 pi
bounded by anyone is 100 pi
bounded by one only is 64 pi

Answer is: 64 PI

Hope that helps!!!

Hatshy [7]3 years ago

5 0

Answer: The area of the region bonded by two concentric circles with radii 10 inches and 6 inches is $64\pi$ in²

Step-by-step explanation:

Here, two circles having radius 10 inches and 6 inches are concentric,

Also, the area of the region bounded by these circles = Area of large circle - Area of small circle. ( Circle having greater radius is called large circle while having smaller area is called small circle )

= $\pi (10)^2 - \pi(6)^2$

= $\pi( 10^2 - 6^2)$

= $\pi ( 100 - 36 )$

= $64\pi\text{ square inches }$

Hence, The area of the region bonded by two concentric circles with radii 10 inches and 6 inches is $64\pi$ in²

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"is it appropriate to use the normal approximation for the sampling distribution of"

Katyanochek1 [597]

Answer: Normal approximation can be used for discrete sampling distributions, such as Binomial distribution and Poisson distribution if certain conditions are met.

Step-by-step explanation: We will give conditions under which the Binomial and Poisson distribitions, which are discrete, can be approximated by the Normal distribution. This procedure is called normal approximation.

1. Binomial distribution: Let the sampling distribution be the binomial distribution $B(n,p)$ , where $n$ is the number of trials and $p$ is the probability of success. It can be approximated by the Normal distribution with the mean of $np$ and the variance of $np(1-p)$ , denoted by $N(np,np(1-p))$ if the following condition is met:

$n>9\left(\frac{1-p}{p}\right)\text{ and } n>9\left(\frac{p}{1-p}\right)$

2. Poisson distribution: Let the sampling distribution be the Poisson distribution $P(\lambda)$ where $\lambda$ is its mean. It can be approximated by the Normal distribution with the mean $\lambda$ and the variance $\lambda$ , denoted by $N(\lambda,\lambda)$ when $\lambda$ is large enough, say $\lambda>1000$ (however, different sources may give different lower value for $\lambda$ but the greater it is, the better the approximation).

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3 years ago

⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ b(1)=−2 b(n)=b(n−1)−7 Find the 3 rd 3 rd 3, start superscript, start text, r, d, end text, end superscript ter

vitfil [10]

Answer:

-16

Step-by-step explanation:

Given the sequence:

b(n)=b(n−1)−7, where b(1)=−2

b(2)=b(2−1)−7

=b(1)−7

=-2-7

b(2)=-9

Therefore, the 3rd term of the sequence

b(3)=b(3−1)−7

=b(2)-7 (Recall b(2)=-9 from above)

=-9-7

b(3)=-16

The 3rd term of the sequence is -16.

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3 years ago

Charles owns a catering business. The amount his 10 most recent clients spent is shown in the histogram below. Why is the graph

Alexxandr [17]

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3 years ago

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What is the answer to 36÷9 using a number line?

Katarina [22]

To divide 36/9 using the number line you have to jump from zero with length of 9 until reach 36, and the result will be the number of jumps.

I do the jumps by steps, but you can draw in the number line:

0. First jump from 0 to 9.

1. Second jump from 9 to 9+9=18.

2. Third jump from 18 to 18+9=27.

3. Fourth jump from 27 to 27+9=36.

4. Great!! We already reach 36.

So, we need four jumps of 9 to reach 36 from 0.

So, the result is 36/9=4

4 0

1 year ago

The volume of a cone is 339.12 if the radius is 6 meters calculate the height

Natali5045456 [20]

Answer:

9 meters

Step-by-step explanation:

V = 1/3 * pi * r^2 * h

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h = 3 * (339.12)/(36 pi)

h = 9 meters

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3 years ago

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