Answer:
23.34 seconds
Explanation:
Flow rate = 1500
Arrival = 800 vehicle per hour
Cycle c = 60 seconds
Dissipation time = 10 seconds
Arrival time = 800/3600 = 0.2222
Rate of departure = 1500/3600 = 0.4167
Traffic density p = 0.2222/0.4167 = 0.5332
Real time = r
r + to + 10 = c
to = c-r-10 ----1
t0 = p*r/1-p ----2
Equate both 1 and 2
C-r-10 = p*r/1-p
60-r-10 = 0.5332r/1-0.5332
50-r = 0.5332r/0.4668
50-r = 1.1422r
50 = 1.1422r + r
50 = 2.1422r
r = 50/2.1422
r = 23.34 seconds
Answer:
F = 2840.3 N
Explanation:
Given:
- Diameter of window D = 0.3 m
- Midpoint of window from sea level h = 4 m
- Specific gravity of sea water S.G = 1.024
- Density of water p = 1000 kg/m^3
Find:
The hydro-static force F_r acting on the mid-point of the window.
Solution:
- The average pressure P acting on the midpoint of the window:
P = S.G p*g*h
P = 1.024*1000*9.81*4
P = 40181.76
- The hydro-static force F_r acting on the mid-point of the window:
F = P*A = P*pi*D^2 / 4
F = 40181.76*pi*0.3^2 / 4
F = 2840.3 N
Answer:

Explanation:
<u>The Differential of Multivariable Functions</u>
Given a multivariable function V(r,h), the total differential of V is computed by

The volume of a cylinder of radius r and height h is

Let's compute the partial derivatives


The total differential is

The differential dr is approximated to
and the differential dh is approximated to
. We can see the increment of radius is the thick of the metal in the sides, and the increment of the height is the thick of the metal in the top and bottom. Thus dr=0.05 cm, dr=0.2 cm


Answer:

Explanation:
given data:
latent heat of fusion 
surface free energy = 0.204 j/m2
meltinf point = 1538 degree celcius

critical radius is given as



activation free energy is given as

