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2 years ago

Is it permissible to install recessed fixture directly against wood ceiling joists? Explain why or why not.

Engineering

1 answer:

masha68 [24]2 years ago

6 0

Answer:

Explanation:

It is not permissible to install recessed fixture directly against wood ceiling joists when the label on the fixture does not indicate that it can be used for Insulation in contact with the recessed fixture .

Because The trim finishing and points of support of openings in finished surfaces are not allowed to be in contact with the combustible materials

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Which of the following does a finding of no significant impact (FONSI) negate the need for?

garik1379 [7]

4 environmental accessment

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2 years ago

Why do you think the Combination Square is better to use than the tape

Tatiana [17]

Answer:

The correct answer to the following question will be "Because the head acts as a stop".

Explanation:

Since the head serves as either a stopping (especially in comparison to something like a floppy tape clip or hanger), the combination square seems to be more reliable and accurate than those of the tape measure.
And maybe you'll know that certain style outlines are still square to something like the sides or finishes.

So that the above seems to be the right answer.

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2 years ago

Given an aerated lagoon with a depth of 9.4 meters receives wastes containing 15 mg/L of biologically degradable material (Q = 8

Anika [276]

Answer:

Surface area of lagoon will be 10.34 ha

Explanation:

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2 years ago

Kerosene flows through 3/4 standard type K drawn copper tube. The pressure drop measured at two points 50 m apart is 130 kPa. De

Anettt [7]

Answer:

$Q=4.98\times 10^{-3}\ m^3/s$

Explanation:

Given that

L= 50 m

Pressure drop = 130 KPa

For Copper tube is 3/4 standard type K drawn tube

Outside diameter=22.22 mm

Inside diameter=18.92 mm

Dynamic viscosity for kerosene

$\mu =0.00164\ Pa.s$

Pressure difference given as

$\Delta P=\dfrac{128\mu QL}{\pi d_i^4}$

Where

L is length of tube

μ is dynamic viscosity

Q is volume flow rate

d is inner diameter of tube

ΔP is pressure drop

Now by putting the values

$\Delta P=\dfrac{128\mu QL}{\pi d_i^4}$

$130\times 1000=\dfrac{128\times 0.00164\times 50\times Q}{\pi\times 0.0189^4}$

$Q=4.98\times 10^{-3}\ m^3/s$

So flow rate is $Q=4.98\times 10^{-3}\ m^3/s$

7 0

2 years ago

The gas velocity decrease from 480 m/s to 160 m/s through a stationary normal shock. If the pressure and density upstream of the

Ainat [17]

Answer:

52m/s

12 kpa

0.1 kg/m

Explanation:

make me brainless tyyy

6 0

1 year ago