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Reika [66]
3 years ago
8

n open feedwater heater operates at steady state with liquid water entering inlet 1 at 10 bar, 50°C. A separate stream of steam

enters inlet 2 at 10 bar and 200°C with a mass flow rate of 16 kg/s. Saturated liquid at 10 bar exits the feedwater heater at exit 3. Ignoring heat trans-fer with the surroundings and neglecting kinetic and potential energy effects, determine the mass flow rate, in kg/s, of the steam at inlet

Engineering
1 answer:
bonufazy [111]3 years ago
8 0

Answer:

Detailed step wise solution is attached

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3 years ago
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When using fall arrest, free fall must be kept at or below how many feet
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<h3>Answer:</h3>

two feet or less

<h3>Explanation:</h3>

8 0
3 years ago
The force of T = 20 N is applied to the cord of negligible mass. Determine the angular velocity of the 20-kg wheel when it has r
horrorfan [7]

Image of wheel is missing, so i attached it.

Answer:

ω = 14.95 rad/s

Explanation:

We are given;

Mass of wheel; m = 20kg

T = 20 N

k_o = 0.3 m

Since the wheel starts from rest, T1 = 0.

The mass moment of inertia of the wheel about point O is;

I_o = m(k_o)²

I_o = 20 * (0.3)²

I_o = 1.8 kg.m²

So, T2 = ½•I_o•ω²

T2 = ½ × 1.8 × ω²

T2 = 0.9ω²

Looking at the image of the wheel, it's clear that only T does the work.

Thus, distance is;

s_t = θr

Since 4 revolutions,

s_t = 4(2π) × 0.4

s_t = 3.2π

So, Energy expended = Force x Distance

Wt = T x s_t = 20 × 3.2π = 64π J

Using principle of work-energy, we have;

T1 + W = T2

Plugging in the relevant values, we have;

0 + 64π = 0.9ω²

0.9ω² = 64π

ω² = 64π/0.9

ω = √64π/0.9

ω = 14.95 rad/s

4 0
4 years ago
An agricultural manager requires
sp2606 [1]
C, being able to maintain legal information on grant programs
3 0
3 years ago
A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly att
love history [14]

Complete Question

For each of the following experiments, identify the counting rule that is relevant for determining the number of experimental outcome.Then use the counting rules to determine the number of experimental outcome

First Experiment

A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly attached , followed by the weight of the can (as less than 14 ounces, exactly 14, or more than 14 ounces).

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Second Experiment

Three branches (A,B, and C) of a bank have open manager positions. Three home-office employees from a pool of five are randomly selected to fill the manager positions. The first home-office employee selected becomes the manager of branch A, the second becomes the manager of branch B, and the third becomes manager of branch C.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Third Experiment

A stockbroker forms a stock portfolio for a client by randomly selecting three stock from a pool of five.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Answer:

First Experiment

Counting rule: Multiple-Step Experiments

Number of Experimental Outcomes: 6

Second Experiment

Counting rule: Permutations

Number of Experimental Outcomes: 60

Third Experiment

Counting rule: Combinations

Number of Experimental Outcomes: 10

Explanation:

The explanation of the first experiment is on the first uploaded image

For the second experiment the counting rule is  permutation because from the experiment we can see that the order of selection  is important

To obtain the Number of Experimental Outcomes:

         We have:  

                         5p_{3} = \frac{5!}{2!}

                               = \frac{5*4*3*2!}{2!}

                              = 60

For the third experiment the the counting rule is combination because the order of selection is not important

To obtain the Number of Experimental Outcomes:

         We have:  

                         5C_{3} =\frac{5!}{3!2!}

                                = 10

   

4 0
3 years ago
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