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Anon25 [30]
2 years ago
5

Which option distinguishes why the behaviors of the team in the following scenario are so important during the engineering desig

n process?
Nico and his team have been working on the design of a new electric billboard. The team has worked together to ensure that they document the project accurately, stick to budgets and time frames, and communicate effectively.

The team members are able to deliver a product that fully meets the client’s needs.
The team members are able to build relationships with the client for future work.
The team members are able to better communicate ideas to other engineering firms that may provide additional help.
The team members are able to make any necessary changes to the design with additional funds they have left over.
Engineering
1 answer:
bezimeni [28]2 years ago
3 0

The option that distinguishes the behaviors of the team in the following scenario are so important during the engineering design process is option a.

<h3>What is teamwork?</h3>

Teamwork is the collaborative attempt of a set to attain a not unusual place aim or to finish a assignment withinside the best and green way. This idea is visible in the more framework of a team, that is a set of interdependent folks that paintings collectively in the direction of a not unusualplace aim.

Thus option A is correct because it does not show the bond in teamwork .The team members are able to deliver a product that fully meets the client’s needs.

Read more about the teamwork:

brainly.com/question/10061787

#SPJ1

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Express the Internal Energy and Entropy as a Function of T and V for a homogeneous fluid. Develop the same relations using the i
DedPeter [7]

Answer:

dU=C_{v} dT+(T(\frac{\beta }{\kappa })  -P)dV

dS=C_{v} \frac{dT}{T} +(\frac{\beta }{\kappa } ) dV

Explanation:

The internal energy is equal to:

dU=C_{v} dT+(T(\frac{\delta P}{\delta T} )_{v} -P)dV

The entropy is equal to:

dS=C_{v} \frac{dT}{T} +(\frac{\delta P}{\delta T} )_{v} dV

If we write the pressure derivative in terms of isothermal compresibility and volume expansivity, we have

\frac{\delta P}{\delta T}=\frac{\beta }{\kappa }

Replacing:

dU=C_{v} dT+(T(\frac{\beta }{\kappa })  -P)dV

dS=C_{v} \frac{dT}{T} +(\frac{\beta }{\kappa } ) dV

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In contrast to the leading-trailing drum brake system, the duo-servo drum brake system will:
prohojiy [21]

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6 0
3 years ago
What chemicals go into lake michigan
solniwko [45]

Answer:

They include PCBs, dioxins, furans, hexachlorobenzene, benzo(a)pyrene (one of many polyaromatic hydrocarbons or PAHs), lead and mercury compounds and pesticides (toxaphene, mirex, aldrin/dieldrin, DDT). 3 Great Lakes Water Quality Agreement Work Group Report on Chemicals of Emerging Concern, August 2009.

7 0
4 years ago
Read 2 more answers
2. Testing Encryption Validity Encryption is the process of converting information algorithmically so that only a valid recipien
4vir4ik [10]

OLAP (online analytical processing) software is the software to perform various high-speed analytics of large amounts of data from a data center, data mart, or other integrated, centralized data store.

<h3>What is the use of Online Analytical Processing (OLAP)?</h3>

OLAP provides pre-calculated data for various data mining tools, business modeling tools, performance analysis tools, and reporting tools.

OLAP can help with Planning and Budgeting andFinancial Modeling. Online Analytical Processing (OLAP) is included in many Business Intelligence (BI) software applications. It is used for a range of analytical calculations and other activities.

Therefore, OLAP (online analytical processing) software is the software to perform various high-speed analytics of large amounts of data from a data center, data mart, or other integrated, centralized data store.

Learn more about Online Analytical Processing (OLAP):

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7 0
1 year ago
Three spheres are subjected to a hydraulic stress. The pressure on spheres 1 and 2 is the same, and they are made of the same ma
r-ruslan [8.4K]

Answer:

"150000 N/m²" is the right approach.

Explanation:

According to the question, the pressure on the two spheres 1 and 2 is same.

Sphere 1 and 2:

Then,

⇒  P_1=P_2

⇒  \frac{\Delta V_1}{V_1}=\frac{\Delta V_2}{V_2}

and the bulk modulus be,

⇒  B_1=B_2

Sphere 3:

⇒  \frac{\Delta V_3}{V_3} =\frac{\frac{\Delta V_1}{V_1} }{\frac{\Delta V_2}{V_2} } =1

then,

⇒  P_3=B\times \frac{\Delta V_3}{V_3}

⇒       =B\times 1

⇒       =150000\times 1

⇒       =150000 \ N/m^2

5 0
3 years ago
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