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Anon25 [30]
2 years ago
5

Which option distinguishes why the behaviors of the team in the following scenario are so important during the engineering desig

n process?
Nico and his team have been working on the design of a new electric billboard. The team has worked together to ensure that they document the project accurately, stick to budgets and time frames, and communicate effectively.

The team members are able to deliver a product that fully meets the client’s needs.
The team members are able to build relationships with the client for future work.
The team members are able to better communicate ideas to other engineering firms that may provide additional help.
The team members are able to make any necessary changes to the design with additional funds they have left over.
Engineering
1 answer:
bezimeni [28]2 years ago
3 0

The option that distinguishes the behaviors of the team in the following scenario are so important during the engineering design process is option a.

<h3>What is teamwork?</h3>

Teamwork is the collaborative attempt of a set to attain a not unusual place aim or to finish a assignment withinside the best and green way. This idea is visible in the more framework of a team, that is a set of interdependent folks that paintings collectively in the direction of a not unusualplace aim.

Thus option A is correct because it does not show the bond in teamwork .The team members are able to deliver a product that fully meets the client’s needs.

Read more about the teamwork:

brainly.com/question/10061787

#SPJ1

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Argue the importance to society of incorporating green building into an engineer’s designs, with at least two examples.
klio [65]
It is important because now a days we all need help from engineers
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3 years ago
What is the average distance (in terms of R) between the mobile on the fringe of the serving cell and the second and third tier
kramer

Answer:

do you need all work shown for this?

4 0
3 years ago
The time to half-maximum voltage is how long it takes the capacitor to charge halfway. Based on your experimental results, how l
satela [25.4K]

Answer:

Time taken for the capacitor to charge to 0.75 of its maximum capacity = 2 × (Time take for the capacitor to charge to half of its capacity)

Explanation:

The charging of a capacitor/the build up of its voltage follows an exponential progression and is given by

V(t) = V₀ [1 - e⁻ᵏᵗ]

where k = (1/time constant)

when V(t) = V₀/2

(1/2) = 1 - e⁻ᵏᵗ

e⁻ᵏᵗ = 0.5

In e⁻ᵏᵗ = In 0.5 = - 0.693

-kt = - 0.693

kt = 0.693

t = (0.693/k)

Recall that k = (1/time constant)

Time to charge to half of max voltage = T(1/2)

T(1/2) = 0.693 (Time constant)

when V(t) = 0.75

0.75 = 1 - e⁻ᵏᵗ

e⁻ᵏᵗ = 0.25

In e⁻ᵏᵗ = In 0.25 = -1.386

-kt = - 1.386

kt = 1.386

t = 1.386(time constant) = 2 × 0.693(time constant)

Recall, T(1/2) = 0.693 (Time constant)

t = 2 × T(1/2)

Hope this Helps!!!

3 0
3 years ago
Read 2 more answers
Why is the face of the claw on a claw hammer usually a smooth curve? Why isn't it straight or some other shape?
GarryVolchara [31]

Answer:

The face of the claw on the claw hammer is usually a smooth curve so as to improve the ease with which nails are removed when removing nails because as the nail held between the V shaped split claw is being pulled out from the wood, it slides more and more towards cheek, reducing the distance of the nail from the cheek which is the fulcrum, thereby increasing the mechanical advantage because the location of the hand on the grip remains unchanged

Explanation:

7 0
3 years ago
A 75 ! coaxial transmission line has a length of 2.0 cm and is terminated with a load impedance of 37.5 j75 !. If the relative p
Cerrena [4.2K]

Answer:

4.26

Explanation:

The wavelength λ is given by:

\lambda=v/f=c/nf\\c=speed\ of\ light=3*10^8m/s,f=frequency=3*10^9Hz,n=permittivity=2.56\\\\\lambda=3*10^8/(2.56*3*10^9)=0.0625\ m\\

Phase constant (β) = 2π/λ

βl = 2π/λ × l

l = 2 cm = 0.02 m

βl = 2π/0.0625 × 0.02=2.01 rad = 115.3°

1 rad = 180/π degrees

Z_L=load\ impedance=37.5+j75\\\\Z_o=characteristic impedance = 75\ ohm\\\\\tilde {Z_L}=Z_L/Z_o=37.5+j75/75=0.5+j

\tilde {Z_{in}}=\frac{\tilde {Z_{L}}+jtan\beta l}{1+j\tilde {Z_{L}}tan\beta l}=\frac{0.5+j+jtan(115.2)}{1+j(0.5+j)tan(115.2)}=0.253-j0.274\\  \\Z_{in}=Z_o\tilde {Z_{in}}=75(0.253-j0.274)=19-j20.5\\\\\Gamma_L=\frac{Z_L-Z_0}{Z_L+Z_o}=\frac{37.5+j75-75}{37.5+j75+75}=0.62\angle 83^o\\\\\Gamma_{in}=\frac{Z_{in}-Z_0}{Z_{in}+Z_o}=\frac{19-j20.5-75}{19-j20.5+75}=0.62\angle -147^o\\\\VSWR=\frac{1+\rho}{1-\rho} =\frac{1+0.62}{1-0.62}=4.26

6 0
3 years ago
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