(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
I would say take 2 from eight which equals 6
Answer:
where is the picture???
what are the given lengths?
The slope is the change in Y over the change in X.
Use the two blue dots on the graph :
(-1,0) ans (3,4)
Slope = (4 - 0) / (3 - -1)
= 4 / 4
= 1
Answer:
The significance level is
and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

So we reject the null hypothesis is 
Step-by-step explanation:
For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:
Null hypothesis: 
Alternative hypothesis: 
And the statistic is given by:

The significance level is
and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

So we reject the null hypothesis is 