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Flura [38]
3 years ago
12

ariana has $4 to spend at the candy shop she wants at least 10 sour snaps which are 15 cents each and at least 3 chocolate truff

les which are 80 cents each which of the following systems of inequalities correctly represents the constraints on the variables in this problem let s represent the sour snaps and t represent the chocolate truffles
Mathematics
2 answers:
Maurinko [17]3 years ago
6 0
15s+80t is less than or equal to 400
15s shows that each sour snap costs 15 cents, 80t shows that each truffle costs 80 cents, and she only has 4 dollars, or 400 cents, so it's less than or equal to.
s is greater than or equal to 10
She wants at least 10
t is greater than or equal to 3
She wants at least 3
34kurt3 years ago
5 0

Answer: The required system of inequalities is,

0.15s + 0.80t ≤ 4,

s ≥ 10, t ≥ 3

Step-by-step explanation:

Here, s represents the the number of sour snaps and t represent the number of chocolate truffles,

Since, she wants at least 10 sour snaps and at least 3 chocolate truffles,

⇒ s ≥ 10 and t ≥ 3,

Also, the cost of one sour snap = 15 cents = $ 0.15

⇒ The cost of s sour snap = 0.15s dollars,

Now, the cost of one chocolate truffle = 80 cents = $ 0.80,

⇒ The cost of t chocolate truffle = 0.80t dollars,

Thus, the total spending = (0.15s + 0.80t) dollars,

According to the question,

The total spending ≤ $ 4,

⇒ 0.15s + 0.80t ≤ 4

Hence, the required system of inequalities that correctly represents the constraints on the variables in this problem is,

0.15s + 0.80t ≤ 4,

s ≥ 10, t ≥ 3

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3 years ago
A square garden plot measures 180 square feet. A second square garden plot measures 320 square feet. How many more feet of fence
REY [17]

The second garden plot will require 8√5 feet more fence than the first garden plot.

Further explanation:

In order to find the fence, we have to find the perimeter of both squares

So,

Area of Square 1: A1=180 square feet

Area of Square 2: A2=320 Square feet

Let x be the side of square 1:

Then,

A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}

For second square:

Let y be the side of second square

A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}

Perimeter of First Square:

P_1=4x\\=4(6\sqrt{5})\\=24\sqrt{5}\ feet

Perimeter of Second Square:

P_2=4y\\=4(8\sqrt{5})\\=32\sqrt{5}\ feet

The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.

P_2-P_1=32\sqrt{5}-24\sqrt{5}\\=(32-24)\sqrt{5}\\=8\sqrt{5}\ feet

The second garden plot will require 8√5 feet more fence than the first garden plot.

Keywords: Radicals, Operations on Radicals

Learn more about radicals at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

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x=7

Step-by-step explanation:

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x=7

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