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sukhopar [10]
2 years ago
7

Please help marking brainliest if its correct!

Mathematics
1 answer:
anygoal [31]2 years ago
4 0

Answer:

I would say B.120 minutes

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Entomologist heinz kaefer has a colony of bongo spiders in his lab. there are 1000 adult spiders in the colony, and their weight
Vera_Pavlovna [14]
We have to find the probability N(11,2)>12, wherein N(11,2)
is the normal law with mean 11 and standard deviation 2. 
Using a scientific calculator we get the probability 0.3. 

Now multiply by the population which is 1000 like this:
0.3*1000=300.

There is 300 <span>spiders  in the colony which weigh more than 12 grams</span>
6 0
2 years ago
Read 2 more answers
(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^
Sedbober [7]
Hello,

a)
I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\&#10;&#10;= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\&#10;&#10;=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\&#10;&#10;= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\&#10;= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\&#10;&#10;
I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\&#10;I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\&#10;

b)
\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\&#10;= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\&#10;= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\&#10;&#10;&#10;&#10;&#10;

\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\&#10;= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\&#10;&#10;&#10;&#10;&#10;&#10;

c)

I_n=  \dfrac{n-1}{n} * I_{n-2} \\&#10;&#10;I_{2n+1}=  \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\&#10;= \dfrac{2n}{2n+1} * I_{2n-1} \\&#10;= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\&#10;= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\&#10;&#10;I_1=1\\&#10;&#10;




3 0
3 years ago
I’ll mark you brainlist I’ll mark you brainlist write in y=mx+b form
Sergio [31]
Y=-2/1x ivigvyvitvtuyvsybsubeeuwub
7 0
2 years ago
Please help me with this question.
Vesna [10]

Answer:

C

Step-by-step explanation:

C, because the second line keeps adding 6 to it and, the third line keeps adding 7.

5 0
2 years ago
John find 1/5 of the bar chocolate he bought was already eaten by his brother. He eat 3/4 of what was remaining. Find the portio
larisa86 [58]

Answer:

1/5 is left.

Step-by-step explanation:

Portion remaining after the bar was eaten by his brother = 1 - 1/5 = 4/5.

Portion remaining after John ate 3/4 of this = 4/5 - 3/4* 4/5 = 4/5 - 3/5

=  1/5.

3 0
3 years ago
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