All categories

3 years ago

One way to limit deforestation is by

2 answers:

6 0

One way to limit deforestation by practicing crop rotation. The correct option among all the options given in the question is option "a". Crop rotation will keep the farmers from further cutting of forests to gain fresh lands. This will also decrease the use of wood products. The soil will also gain strength due to rotation of crop.

iogann1982 [59]3 years ago

6 0

Answer:

d. using wood from trees grown on tree farms.

Explanation:

You might be interested in

A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at

makvit [3.9K]

Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)

ΔG° = -533.64 kJ

3 0

3 years ago

When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H

Debora [2.8K]

Answer:

$Y=58.15\%$

Explanation:

Hello,

For the given chemical reaction:

$Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)$

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

$n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3$

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

$n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3$

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

$m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3$

Finally, we compute the percent yield with the obtained 2.10 g:

$Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%$

Best regards.

7 0

2 years ago

What was Newtons first law of motion??

Ksivusya [100]

Answer:

Basically an object in motion or at rest will remain that way unless an outside force acts against it.

Explanation:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia.

4 0

3 years ago

Read 2 more answers

Is the following a redox reaction? Explain.<br> NH₃(aq) + HCl(aq) → NH₄Cl(aq)

jeyben [28]

The process is not a redox reaction.

The reaction between ammonia $(NH_{3} )$ and hydrochloric acid (HCl) to produce ammonium chloride ( $NH_{4} Cl$ ) has modified the oxidation number of no atom in the reactants. As a base, ammonia interacts easily with hydrochloric acid to produce ammonium chloride salt. A neutralization reaction between an acid and a base is what the described process is, and it is NOT a redox reaction.

A reaction is referred to as a redox reaction if two or more reactants belonging to a single reaction exchange one or more electrons, i.e., one reactant releases one or more additional electrons while the other obtains one or additional electrons. The reacted substance that releases electrons is oxidized and becomes a reducing substance. A reduced oxidizing agent is the reactant that accepts electrons.

Learn more about redox reaction: brainly.com/question/13293425

#SPJ4

3 0

1 year ago

__C8H18(I) + __ O2(g) —> __Co2(g) + __H2O(g) Balance out the equation

Ymorist [56]

Answer:

2C8H18(l) + O2(g)--->CO2(g)+H2O

3 0

2 years ago