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slava [35]
3 years ago
13

Assume that 1.0 mol of C4H10 is completely burned in excess oxygen to form carbon dioxide and water. How many moles of CO2 would

be produced?
Chemistry
1 answer:
In-s [12.5K]3 years ago
7 0
You need to first write a chemical equation and balance it
 C₄H₁₀ + O₂ → CO₂ + H₂O
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
1.0 moles               X moles
1.0 mol C₄H₁₀ (\frac{8 mol CO₂}{2 mol C₄H₁₀}) = 4 moles of CO₂
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what is the wavelength of a photon emitted when an electron jumps from n=2 to n= 1 energy level of a single ionized helium atom
Neko [114]

Answer:

I hope it help you the wavelength is 1.9130E-28

7 0
3 years ago
On what information did Thomson base his hypothesis that atoms contain positive particles?
ElenaW [278]

Answer:

If you have any more questions text 3856026122

Explanation:

J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged soup

4 0
3 years ago
Which factor contributes the most to the rates of diffusion and effusion between two gases in a mixture?
sergejj [24]

Answer:

b)The molar mass of the particles.

Explanation:

The rate of effusion of a gas is inversely proportional to the square root of its molar mass (Graham's law), a relationship that closely approximates the rate of diffusion. As a result, light gases tend to diffuse and effuse much more rapidly than heavier gases.

5 0
3 years ago
what electronic transition in a hydrogen atom starting from n=7 energy level will produce infrared radiation with energy of 55.1
Lostsunrise [7]

Answer:

(<em>n</em> = 7) ⟶ (<em>n</em> = 4)

Explanation:

1. Convert the energy to <em>joules per mole of electrons</em>.  

<em>E</em> = 55.1 × 1000 = 55 100 J/mol

2. Convert the energy to <em>joules per electron </em>

<em>E</em> = 55 100/(6.022 × 10²³)

<em>E</em> = 9.150 × 10⁻²⁰ J/electron

3. Use the Rydberg equation to <em>calculate the transition </em>

Rydberg's original formula was in terms of wavelengths, but we can rewrite it to have the units of energy. The formula then becomes  

\Delta E = R_{\text{H}} (\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ n_{i}^{2}})

where  

R_{\text{H}} = the Rydberg constant = 2.178 × 10⁻¹⁸ J

n_{i} and n_{f} are the initial and final energy levels.

9.150 \times 10^{-20} = 2.178 \times 10^{-18}(\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 7^{2}})      

\frac{9.150 \times 10^{-20} }{2.178 \times 10^{-18}} = \frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 49}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01} + \frac{1 }{49 }

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.062 42}

n_{f}^{2} = \frac{1 }{ \text{0.062 42}}

n_{f}^{2} = 16.02

n_{f} = \sqrt{16.02}

n_{f} = 4.003 \approx 4

4 0
3 years ago
Where does the greenhouse effect occur?
attashe74 [19]

Answer:

the greenhouse effect occurs in the earths atmosphere

7 0
3 years ago
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