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slava [35]
3 years ago
13

Assume that 1.0 mol of C4H10 is completely burned in excess oxygen to form carbon dioxide and water. How many moles of CO2 would

be produced?
Chemistry
1 answer:
In-s [12.5K]3 years ago
7 0
You need to first write a chemical equation and balance it
 C₄H₁₀ + O₂ → CO₂ + H₂O
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
1.0 moles               X moles
1.0 mol C₄H₁₀ (\frac{8 mol CO₂}{2 mol C₄H₁₀}) = 4 moles of CO₂
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A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
11Alexandr11 [23.1K]

Answer:

V₂ = 648.53 mL

Explanation:

Given data:

Initial volume of gas = 490. mL

Initial temperature = -35°C (-35 + 273 = 238 k)

Final temperature = 42°C =  (42+273 = 315 k)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 490 mL × 315 K / 238 k

V₂ = 154350 mL.K / 238 K

V₂ = 648.53 mL

8 0
3 years ago
What is the interval used on the y-axis of this graph?
bezimeni [28]

Answer:

5

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the numbers go up by 5

7 0
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In the figure below, two nonpolar molecules are interacting.Which interaction would most likely cause these molecules to repel e
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Two non-polar molecules are most likely to interact by
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Non-polar substances do not have a permanently established charge distribution due to similar electron affinities of the atoms that are present. Moreover, due to the absence of a polar hydrogen, they cannot exhibit hydrogen bonding. They interact with one another by induced dipole-induced dipole interactions which arise from the molecules of the substances coming into close vicinity of one another.
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A

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