Which type of variable is most related to the data gathered from an experiment?

A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?

AfilCa [17]

First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)

3 0

3 years ago

Gold-leaf electroscope uses

Kruka [31]

-identifies an electric charge
-it can identify its polarity (positive or negative) if you compare it to a charge that you already know
-can identify the magnitude of a charge (how big of a charge it is)

7 0

4 years ago

A hockey puck slides across the ice with an initial velocity of 7.3 m/s .It has a decleration of 1.1 m/s and is traveling toward

sashaice [31]

Answer:

t = 6.63 s

Explanation:

Given that,

Initial velocity of the puck, u = 7.3 m/s

Deacceleration of the puck, a = -1.1 m/s²

Distance traveled, d = 5 m

We need to find the time the goalie have to stop the puck. Using equation of motion.

v = u +at

v = 0 (stops)

So,

$u=-at\\\\t=\dfrac{u}{-a}\\\\t=\dfrac{7.3}{-(-1.1)}\\\\t=6.63\ s$

So, the required time is 6.63 seconds.

6 0

3 years ago

Calculate the electrostatic force that a small sphere A, possessing a net charge of 2.0 x 10^-6 Coulombs exerts on another small

Anni [7]

Answer:

F = 5.33*10^-4N

Explanation:

to find the electrostatic force you use the Coulomb's law, given by the formula:

$F=k\frac{q_Aq_B}{r^2}$

k: Coulomb's constant = 8.89*10^9 Nm^2/C^2

q_a: charge of A = 2.0*10^{-6}C

q_B: charge of B = -3.0*10^{-6}C

r: distance between the spheres = 10.0m

By replacing all these values you obtain:

$F=(8.89*10^9Nm^2/C^2)\frac{(2.0*10^{-6}C)(-3.0*10^{-6}C)}{(10.0m)^2}=5.33*10^{-4}N$

hence, the forcebetween the spheres is about 5.33*10^-4N

3 0

3 years ago

#27 question

Furkat [3]

So, the initial altitude of the parachuter is approximately <u>(C). 123 m</u>.

<h2>Introduction</h2>

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the following equations apply:

<h3>The equation for calculating the height (h)</h3>

$\boxed{\sf{\bold{h = \frac{1}{2} \cdot g \cdot t^2}}}$

<h3>The equation for calculating the time (s)</h3>

$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

<h3>The equation for calculating the velocity (v)</h3>

$\boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)
v = velocity (m/s)

<h2>Problem Solving</h2>

We know that :

t = interval of the time = 5 s
g = acceleration of the gravity = 9.81 m/s²

What was asked :

h = height or displacement at vertical line = ... m

Step by Step :

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

$\sf{h = \frac{1}{2} \cdot 9.81 \cdot 5^2}$

$\sf{h = \frac{245.25}{2}}$

$\boxed{\sf{h = 122.625 \: m \approx 123 \: m}}$

<h3>Conclusion</h3>

So, the initial altitude of the parachuter is approximately 123 m (C.)

Time that needed for hearing the splash of fallen rock in the well brainly.com/question/26485521
The speed of the object at a certain height (free fall motion) brainly.com/question/26377041
The relationship between acceleration and the change in velocity and time in free fall brainly.com/question/26486625

4 0

2 years ago

Which type of variable is most related to the data gathered from an experiment?​

Which type of variable is most related to the data gathered from an experiment?