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Alex787 [66]
3 years ago
15

Suppose you have three springs with force constants of k1 = k2 = k3 = 3.70 x 10^3 N/m. What is their effective force constant if

one is hung from the other in series? You may assume the springs have negligible mass.
The answer should be in N/m.
Physics
1 answer:
disa [49]3 years ago
6 0

Answer:

The effective force constant is 1233.33 N/m.

Explanation:

It is given that,

Force constant 1, k_1=3.7\times 10^3\ N/m

Force constant 2, k_2=3.7\times 10^3\ N/m

Force constant 3, k_3=3.7\times 10^3\ N/m

The effective force constant if one is hung from the other in series is given by :

\dfrac{1}{K_{eff}}=\dfrac{1}{k_1}+\dfrac{1}{k_2}+\dfrac{1}{k_3}

\dfrac{1}{K_{eff}}=\dfrac{1}{3.7\times 10^3}+\dfrac{1}{3.7\times 10^3}+\dfrac{1}{3.7\times 10^3}

K_{eff}=1233.33\ N/m

So, the effective force constant is 1233.33 N/m. Hence, this is the required solution.

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Answer:

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Explanation:

Vi = 75 m/s

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t = 50 s

Plug those values into the following equation:

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If the ball that is thrown downward has an acceleration of magnitude aaa at the instant of its release (i.e., when there is no l
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Explanation:

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A 2.0kg rock is thrown straight up into the air with a speed of 30m/s. Ignore air resistance. What is the net force acting on th
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Answer:

19.6N

Explanation:

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A heat engine exhausts 3 000 J of heat while performing 1 500 J of useful work. What is the efficiency of the engine
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Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.
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Answer:

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Solution:

            Given:

                     speed, v = 8 m/s

                 distance, d = 20m

                     

              To Find:

                     deacceleration = ?

               

               As we know speed is defined as

                          v = d/t

                plugging in the values

                          t =  20/ 8

                          t = 2.5s

                Now from deceleration formula

                        a =  - v/ t

                        a = - 20/ 2.5

                        a = - 8 m/s²

          Thus, the time taken and acceleration is 2.5 s and -8 m/s²

          respectively.

          Learn more about deceleration here:

                brainly.com/question/13354629

                       #SPJ4  

               

                       

             

7 0
2 years ago
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