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Vladimir79 [104]
3 years ago
9

You climb to the top of a ladder. You drop a a ball from height H, it reaches the ground with speed V if there is no air resista

nce. From what height should you drop it so it will reach the ground with three times the original speed?
√3H
H
6H
9H


(pls help its due today)
Physics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

heymelissa its amanda i hate ms spearman

Explanation:

yuh

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Your answer is B.

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A rock is thrown from a bridge at an angle 30∘ below horizontal.immediately after the rock is released, is the magnitude of its
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3 years ago
If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m
algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

H=ut+\dfrac{1}{2}at^2

Here, a = g

H=\dfrac{1}{2}gt^2            

H=\dfrac{1}{2}\times 9.8\times (2.261)^2

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

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An 88 kg worker stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale reads 900 N. Fi
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Answer:

The magnitude is "3.8 m/s²", in the upward direction.

Explanation:

The given values are:

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m = 88 kg

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On substituting the given values, we get

⇒      =88\times 9.8

⇒      =862.4 \ N

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⇒  T=mg-ma

On substituting the given values in the above equation, we get

⇒  900=862.4-9.8 a

On subtracting "862.4" from both sides, we get

⇒  900-862.4=862.4-9.8 a-862.4

⇒              37.6=-9.8a

⇒                   a=-\frac{37.6}{9.8}

⇒                   a=3.8 \ m/s^2 (upward direction)

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Answer:

True! UwU

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