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Ira Lisetskai [31]
3 years ago
14

Calculate the molarity of a solution made by adding 45.4 g of nano3 to a flask and dissolving it with water to create a total vo

lume of 2.50 l. express your answer to three significant figures.

Chemistry
2 answers:
Zigmanuir [339]3 years ago
5 0

The molarity of a solution made by adding 45.4 g of NaNO3 to a flask and dissolving it with water to create a total volume of 2.50 L is <u>0.213 M. </u>

<h2>Further Explanation: </h2><h3>Molarity  </h3>
  • Molarity may be defined as the concentration of a solution in moles per liter. It is calculated by dividing the number of moles of a solution, n by its volume in liters, V.  
  • That is; Molarity = n/V, where n is the number of moles and V is the volume in liters.  
  • Therefore; when given the molarity of a solution and the volume of the solution, then we can get the number of moles, by multiplying the molarity by volume;  
  • Number of moles = Molarity x Volume
  • Additionally, the number of moles of a compound or an element can also be calculated by dividing the mass of the compound by its relative molecular mass.
<h3>In this case:  </h3>
  • Mass of NaNO3 = 45.4 g  
  • But: Number of moles = Mass/ Molar mass
  • Molar mass of NaNO3 is 84.995 g/mol  
  • Thus; Number of moles = (45.4 g)/(84.995 g/mol)

                                      = 0.534 moles  

  • Volume of the solution = 2.50 L  

But; Molarity = Number of moles/ Volume  

                     = 0.534 moles/2.50 L

                     = 0.2136 Moles/Liter  

                     <u>= 0.213 M</u>  

Keywords: Molarity, Moles, Volume

<h3>Learn more about:  </h3>
  • Molarity: brainly.com/question/12834126
  • Relationship between moles, molarity and volume: brainly.com/question/12834126

Grade: Middle  School

Subject: Chemistry

Chapter: Mole and stoichiometry equations

aleksandr82 [10.1K]3 years ago
3 0
Solutions are made up of two non reacting species called solute and solvent. The amount of solute in solvent is known as concentration of that solute. Concentration is often measured in Molarity. Molarity is the amount of solute dissolved in 1 dm3 of solution. Answer to your question is as follow;

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<h3>Answer:</h3>

                      2.55 × 10²² Na Atoms

<h3>Solution:</h3>

Data Given:

                 M.Mass of Na  =   23 g.mol⁻¹

                 Mass of Na  =  973 mg  =  0.973 g

                 # of Na Atoms  =  ??

Step 1: Calculate Moles of Na as:

               Moles  =  Mass ÷ M.Mass

               Moles  =  0.973 g ÷ 23 g.mol⁻¹

               Moles  =  0.0423 mol

Step 2: Calculate No, of Na Atoms as:

As 1 mole of sodium atoms counts 6.022 × 10²³ and equals exactly to the mass of 23 g. So, we can write,

               Moles  =  No. of Na Atoms ÷ 6.022 × 10²³ Na Atoms.mol⁻¹

Solving for No. of Na Atoms,

               No. of Na Atoms  =   Moles × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =   0.0423 mol × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =  2.55 × 10²² Na Atoms

<h3>Conclusion: </h3>

                          2.55 × 10²² sodium atoms are required to reach a total mass of 973 mg in a substance of pure sodium.


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