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3 years ago

What is the general structure for a chemical equation?

1 answer:

kramer3 years ago

6 0

A chemical formula is a way of expressing information about the proportions of atoms that constitute a particularchemical compound, using a single line of chemical element symbols, numbers, and sometimes also other symbols, such as parentheses, dashes, brackets, commas and plus (+) and minus (−) signs. A chemical formula is not a chemical name showing how the atoms are arranged.

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Which of these defines a volcano?

dalvyx [7]

The answer is b!!! !!!

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3 years ago

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A solution of NaCl ( aq ) is added slowly to a solution of lead nitrate, Pb ( NO 3 ) 2 ( aq ) , until no further precipitation o

statuscvo [17]

Answer : The molarity of $Pb(NO_3)_2$ solution is, 0.352 M

Explanation :

First we have to calculate the moles of $PbCl_2$

$\text{Moles of }PbCl_2=\frac{\text{Given mass }PbCl_2}{\text{Molar mass }PbCl_2}$

Molar mass of $PbCl_2$ = 278.1 g/mol

$\text{Moles of }PbCl_2=\frac{19.58g}{278.1g/mol}=0.07041mol$

Now we have to calculate the moles of $CaCl_2$

The balanced chemical equation is:

$Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)$

From the balanced reaction we conclude that

As, 1 mole of $PbCl_2$ produced from 1 mole of $Pb(NO_3)_2$

So, 0.07041 mole of $PbCl_2$ produced from 0.07041 mole of $Pb(NO_3)_2$

Now we have to calculate the molarity of $Pb(NO_3)_2$

$\text{Molarity of }Pb(NO_3)_2=\frac{\text{Moles of }Pb(NO_3)_2}{\text{Volume of solution in (L)}}$

$\text{Molarity of }Pb(NO_3)_2=\frac{0.07041mol}{0.200L}=0.352M$

Therefore, the molarity of $Pb(NO_3)_2$ solution is, 0.352 M

4 0

3 years ago

The number of grams of H2 in 1470 mL of H2 gas.

Lorico [155]

Answer:

0.1313 g.

Explanation:

It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.

Suppose that hydrogen behaves ideally and at STP conditions.

Using cross multiplication:

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen = (6.563 x 10⁻² mol)(2.0 g/mol) = 0.1313 g.

5 0

3 years ago

Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th

lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this orange line is 3.26 x 10⁻¹⁹ J.

"Your question is not complete, it seems to be missing the diagram of the emission spectrum"

the diagram of the emission spectrum has been added.

From the given chart;

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

c is the speed of light = 3 x 10⁸ m/s
f is the frequency of the wave
λ is the wavelength

$f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz$

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ Js

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this orange line is 3.26 x 10⁻¹⁹ J.

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2 years ago

All molecular motion stops at 0 on this scale

Oxana [17]

Kelvin Hope this helps

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3 years ago

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