1 and 3 ???
not nuclear ... chemical (outside the nucleus)
energy is v v v often lost as heat.
Answer:
Charles law explains that volume is directly proportional to temperature
Explanation:
- u would equate V1/T1=V2/T2
- U are looking for V2 since u already have V1 , T1 and T2
Initial speed of Gazelle is along x direction and its value will be
![v_x = 5.6 m/s](https://tex.z-dn.net/?f=v_x%20%3D%205.6%20m%2Fs)
also its initial height is given as
![y = 2.5 m](https://tex.z-dn.net/?f=y%20%3D%202.5%20m)
Part a)
now from kinematics along Y direction
![\Delta y = v_y t + \frac{1}{2} at^2](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%20v_y%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
as we know that
![\Delta y = 0](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%200)
![v_y = 0](https://tex.z-dn.net/?f=v_y%20%3D%200)
![a = 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.8%20m%2Fs%5E2)
![2.5 = 0 + \frac{1}{2} (9.8) t^2](https://tex.z-dn.net/?f=2.5%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%289.8%29%20t%5E2)
![t = 0.714 s](https://tex.z-dn.net/?f=t%20%3D%200.714%20s)
Part b)
distance moved horizontally
![\Delta x = v_x t](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20v_x%20t)
as we know that
![v_x = 5.6 m/s](https://tex.z-dn.net/?f=v_x%20%3D%205.6%20m%2Fs)
now we will have
![v_x = 5.6 (0.714) = 4m](https://tex.z-dn.net/?f=v_x%20%3D%205.6%20%280.714%29%20%3D%204m)
so it will lend at distance of 4 m.
Part c)
final velocity in vertical direction
![v_{fy} = v_y + at](https://tex.z-dn.net/?f=v_%7Bfy%7D%20%3D%20v_y%20%2B%20at)
![v_{fy} = 0 + (9.8)(0.714) = 7 m/s](https://tex.z-dn.net/?f=v_%7Bfy%7D%20%3D%200%20%2B%20%289.8%29%280.714%29%20%3D%207%20m%2Fs)
![v_x = 5.6 m/s](https://tex.z-dn.net/?f=v_x%20%3D%205.6%20m%2Fs)
so net speed will be
![v^2 = v_x^2 + v_y^2](https://tex.z-dn.net/?f=v%5E2%20%3D%20v_x%5E2%20%2B%20v_y%5E2)
![v^2 = 7^2 + 5.6^2](https://tex.z-dn.net/?f=v%5E2%20%3D%207%5E2%20%2B%205.6%5E2)
![v = 8.96 m/s](https://tex.z-dn.net/?f=v%20%3D%208.96%20m%2Fs)
Answer:
assuming that there is an equal amount of each base, you can make 65,536 bases
Explanation:
Adenine(A) Guanine(G) Thymine(T) and Cytosine(C) are the 4 nitrogen bases.
<span>The sum of the speeds is 9.44 m/s + 9.44 m/s which is 18.88 m/s
Note that the sum of the speeds of the two stones is always 18.88 m/s because as the upward moving stone loses speed, the downward moving stone gains the same amount of speed each unit of time.
We can find the time for the stones to meet.
t = d / v
t = 5.39 m / 18.88 m/s
t = 0.285487 seconds
We can use the upward moving stone to find the height y.
y = v0 t + (1/2) a t^2
y = (9.44 m/s)(0.285487 s) - (1/2) (9.8 m/s^2) (0.285487 s)^2
y = 2.30 m
The two stones cross paths a height of 2.30 meters above the base of the cliff.</span>