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Anna35 [415]
4 years ago
9

Why is the bond angle in a water molecule less than the bond angle of methane

Chemistry
1 answer:
Annette [7]4 years ago
6 0
The bond angle in the Water Molecule is approx. 104.5 degrees. The methane molecule is approx. 109.5 degrees. The differences, is due to the force from the surrounding molecules and atoms. For example the Lone pairs of electrons.

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What is the enthalpy for the following reaction? overall: C + 1/2O2→CO
telo118 [61]

Answer:

ΔH°(f) = -110.5 Kj/mole (exothermic)

Explanation:

C + 1/2O₂ => CO

This is asking for the 'Standard Heat of Formation (ΔH°(f)* for carbon monoxide (CO). Values for many compounds can be found in the appendix of most college general chemistry text books. From Ebbing & Gammon, 11th edition, General Chemistry, Appendix C, page 8A.

*Standard Heat of Formation by definition is the heat gained or lost on formation of a substance (compound) from its basic elements in standard state.

The ΔH°(f) values as indicated are found in the appendix of most college chemistry texts. By choosing any compound, one can determine the standard heat of formation equation for the substance of interest. For example, consider Magnesium Carbonate; MgCO₃(s).The basic standard states of each element is found in the Appendix on Thermodynamic Properties for Substances at 25°C & 1 atm. having  ΔH°(f) values = 0.00 Kj/mole. All elements in standard state have a 0 Kj/mol. See appendix and note that under the ΔH°(f) symbol some substances have 0.00 Kj/mol values. The associated element will be in basic standard state,

Standard Heat of Formation Equation for formation of Magnesium Carbonate;

Mg°(s) + C°(gpt)* + 3/2O₂(g) => MgCO₃(s) ; ΔH°(f) = -1111.7 Kj/mole

* gpt => graphite

4 0
3 years ago
The water-gas shift reaction CO(g)+H2O(g)⇌CO2(g)+H2(g) is used industrially to produce hydrogen. The reaction enthalpy is ΔH∘=−4
Pani-rosa [81]

Answer:

The answers are in the explanation

Explanation:

A. For the reaction:

CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g);  ΔH°=−41kJ.

As the reaction is exothermic ( ΔH°<0), you need to use low temperature to increase the equilibrium yield of hydrogen -LeChatelier's principle-.

We would use <em>low </em>temperature. For an <em>exothermic </em>reaction such as this, <em>decreasing </em>temperature increases the value of K and the amount of products at equilibrium.

B.

c. No. We cannot increase the equilibrium yield of hydrogen by controlling the pressure of this reaction.

It is possible to increase the equilibrium yield of reaction by controlling the amount of reactants added. As reactants and products are gases, the pressure of the reaction will not change the amount of reactants or products in the equilibrium.

I hope it helps!

8 0
3 years ago
Aerosol cans have a label that warns the user not to use them above a certain temperature and not to dispose of them by incinera
Arturiano [62]

Answer:

1.90 atm

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

According to above equation, at constant Volume and number of moles, pressure is directly proportional to the temperature. So,

\frac {P_1}{T_1}=\frac {P_2}{T_2}

Given ,  

P₁ = 1.51 atm

P₂ = ?

T₁ = 23 °C

T₂ = 100 °C  ( boiling point of water )

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (23 + 273.15) K = 296.15 K  

T₂ = (100 + 273.15) K = 373.15 K  

Using above equation as:

\frac{1.51}{296.15}=\frac{P_2}{373.15}

P_2=\frac{1.51\cdot \:373.15}{296.15}\ atm

<u>New Pressure = 1.90 atm</u>

5 0
3 years ago
Which structures group together to form a system in the human body
Alexxx [7]

Answer:

organs group together to form organ systems

Explanation:

8 0
3 years ago
Q#5. The bond between which two atoms is most polar? ​
Ede4ka [16]

Answer:

H-O

Explanation:

because oxygen and hydrogen have very high difference in electronegativity

8 0
3 years ago
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