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Aleksandr-060686 [28]
3 years ago
12

Be sure to answer all parts. what volumes (in liters) of carbon monoxide and oxygen gas must react according to the equation 2co

(g) + o2(g) → 2co2(g) to form 4.86 l of carbon dioxide? what is the volume of co?
Chemistry
1 answer:
zysi [14]3 years ago
3 0
The  volume of  oxygen  gas  and  carbon  monoxide  that   need to  react  is  calculated  as  follows

write  the  equation  for  reaction

2CO  +O2=  2CO2 
the   reacting  ratio  of CO:O2:CO2  is   2:1:2  from the  equation  above therefore

the  volume  of  O2  =   4.86l  x 1/2=2.43   L  of O2

the  volume  of  CO =  4.86  x2/2 =  4.86 L  of CO
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Answer:

-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}

Explanation:

The rate law of a chemical reaction is given by

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This law can be written for any experiment, and making the quotient between those expressions the reaction orders can be found

Between experiments 1 and 2  

\frac{-r_{A1}}{{-r}_{A2}}=\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)^\beta

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\beta=\frac{ln\frac{-r_{A1}}{-r_{A2}}}{ln\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)}=\frac{ln\frac{0.2130}{0.1065}}{ln\left(\frac{0.250}{0.125}\right)}

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\beta=1

Doing the same between experiments 3 and 4 the expression for \alpha is

\alpha=\frac{ln\frac{-r_{A3}}{-r_{A4}}}{ln\left(\frac{\left[BF_3\right]_3}{\left[BF_3\right]_4}\right)}=\frac{ln\frac{0.0682}{0.1193}}{ln\left(\frac{0.200}{0.350}\right)}

Resolving  

\alpha=1

This means that the rate law for this reaction is  

-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}

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