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ipn [44]
3 years ago
12

How many moles are in 74 g KI?

Chemistry
1 answer:
nexus9112 [7]3 years ago
7 0
N=?
m=74g
n=m:Mr
Mr (Cl)=35,5g/mol
n=74g:35,5g/mol
n=2,08mol
I think this is the answer, hope I am right!
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In the sn2 experiment, what was the purpose of washing the distilled product with 5% naoh
photoshop1234 [79]

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5 0
3 years ago
What is the molarity of a naoh solution if 39.1 ml of a 0.112 m h2so4 solution is required to neutralize a 25.0-ml sample of the
aleksandrvk [35]
The reaction between NaOH and H₂SO₄ is as follows;
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry  of base to acid is 2:1
NaOH is a strong acid and H₂SO₄ is a strong acid, therefore complete ionization into their respective ions takes place.
number of acid moles reacted - 0.112 M / 1000 mL/L x 39.1 mL = 0.0044 mol
the number of base moles required for neutralisation = 0.0044 x 2 = 0.0088 mol
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8 0
3 years ago
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