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ipn [44]
3 years ago
12

How many moles are in 74 g KI?

Chemistry
1 answer:
nexus9112 [7]3 years ago
7 0
N=?
m=74g
n=m:Mr
Mr (Cl)=35,5g/mol
n=74g:35,5g/mol
n=2,08mol
I think this is the answer, hope I am right!
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Calculate the enthalpy change for the reaction of hydrogen and chlorine using the bond energies below.
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8 0
3 years ago
Please answer asap!
hram777 [196]
1.) A compound is a thing that is composed of two or more (separate) elements.

2.) A compound cannot be separated easily, while its properties differ from where it originates from. It also is formed from chemical reactions.

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4 0
3 years ago
Use the atomic mass of indium to calculate the relative abundance of indium-113.
ASHA 777 [7]

The relative abundance of indium-113 is 4%.

The isotopes are species of the same element having the same atomic number but a different mass number.

The elements occurring in nature exist as multiple isotopes.

When we take into account the existence of these isotopes and their relative abundance (percent), the average atomic mass of that element can be computed, which is given by the following formula,

Average atomic Mass= (%age of isotope 1) x (Mass of isotope 1) + (%age of isotope 2) x (Mass of isotope 2)/100

Indium exists in the form of Indium-113 and Indium-115.

The mass of Indium-113 is 112.90 u.

The mass of Indium-115 is 114.90 u.

The average atomic mass of Indium is 114.82 u.

Let the %age of isotope 1(Indium-113) be X.

Then, the %age of isotope 2(Indium-115) would be 100-X.

Applying the values in the formula,

Average atomic mass = 112.90X+114.90(100-X)

114.82 = 112.90X+114.90(100-X)

On solving the above equation, the value of X comes out to be 4%.

Thus, the relative abundance/%age abundance of Indium-113 is 4%.

To know more about "Average Atomic Mass", refer to the following link:

brainly.com/question/13753702?referrer=searchResults

#SPJ4

7 0
1 year ago
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